Rendering HTML inside XML through XSL

jilly · May 23rd, 2007, 12:06 AM

I have this xml in which I have html tags. I want to render the "<myhtml>" (as in example below) tag through my XSL while retaining its formatting. At the moment it is rendering <myhtml> tag's inner content as it is without taking care of any formatting tags :(:(

e.g.

Code:

<top>
   <myhtml>
      Some <b>bold</b> content and some <i>italic</i> content
   </myhtml>
</top>

Thanks in advance :)

mhkay · May 23rd, 2007, 03:44 AM

It's hard to tell what you're doing wrong without seeing your code, but the usual mistake that beginners make (apart from not showing people their code...) is using xsl:value-of in place of xsl:copy-of.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

jilly · May 23rd, 2007, 04:31 AM

Oh just forgot to paste the relevant xsl:

Code:

<?xml version='1.0'?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/TR/WD-xsl"
  xmlns:xs="http://www.w3.org/2001/XMLSchema"
  xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes" >
.. .. ..
.. .. ..
<xsl:for-each select="/formalcomments/annotation" order-by="id">
<tr>

<td><xsl:value-of select="/top/myhtml"/></td>
</tr>

Also tried "/top/myhtml/node()" but it truncated the rest of the node's content as soonas it found first html (<b>) tag.

Using <xsl:copy-of> in place of <xsl:value-of> as per suggestion generated the following error

Code:

Keyword xsl:copy-of may not be used in namespace http://www.w3.org/TR/WD-xsl.

jilly · May 23rd, 2007, 04:46 AM

Posting the code after a little correction (had changed the xml/xsl for simplicity :) )..

Asuming that id exists alongwith myhtml node in XML..

Code:

<?xml version='1.0'?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/TR/WD-xsl"
  xmlns:xs="http://www.w3.org/2001/XMLSchema"
  xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes" >
.. .. ..
.. .. ..
<xsl:for-each select="/top" order-by="id">
<tr>
<td><xsl:value-of select="id"/></td>
<td><xsl:value-of select="myhtml"/></td>
</tr>

Also tried "myhtml/node()" but it truncated the rest of the node's content as soonas it found first html (<b>) tag.

Using <xsl:copy-of> in place of <xsl:value-of> as per suggestion generated the following error

Code:

Keyword xsl:copy-of may not be used in namespace http://www.w3.org/TR/WD-xsl.

[/quote]

mhkay · May 23rd, 2007, 05:14 AM

Oh dear, you are very confused.

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/TR/WD-xsl"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes" >

Namespace http://www.w3.org/TR/WD-xsl defines a variant of XSLT introduced by Microsoft in 1998 before the XSLT 1.0 specs were finished in 1999. It is very rarely seen nowadays, and is not documented or supported, although I believe it still runs in Internet Explorer.

Namespace http://www.w3.org/2005/02/xpath-datatypes identifies a draft of the XSLT 2.0 recommendation (not the final version).

You need to decide which version of XSLT you are trying to use.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

jilly · May 23rd, 2007, 10:28 AM

I got some detailed help from another forum.. here is the solution just incase..

Fixed namespaces..

Code:

<top xmlns:dataType= "urn:schemas-microsoft-com:datatypes">

and

Code:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

Selection by copy-

Code:

<xsl:for-each select="myhtml">
<xsl:copy>
    <xsl:copy-of select="@*"/>
    <xsl:apply-templates mode="copy"/>
</xsl:copy>
</xsl:for-each>

..

Code:

    <xsl:template match="@*|node()" mode="copy">
        <xsl:copy>
            <xsl:copy-of select="@*"/>
            <xsl:apply-templates mode="copy"/>
        </xsl:copy>
    </xsl:template>

jilly · May 23rd, 2007, 10:36 AM

Code:

<xsl:for-each select="myhtml">
    <xsl:apply-templates mode="copy"/>
</xsl:for-each>

instead of..

Code:

<xsl:for-each select="myhtml">
<xsl:copy>
    <xsl:copy-of select="@*"/>
    <xsl:apply-templates mode="copy"/>
</xsl:copy>
</xsl:for-each>