But I have done this.

You see that I have close the templates with:
</xsl:call-template>

<xsl:call-template name="statusReport">
<xsl:with-param name="status">Find</xsl:with-param>
</xsl:call-template>

It's not xsl:call-template that's the issue, it's xsl:template.

I'm afraid this is getting a bit childish. You'll be asking me where the shift key on your keyboard is next.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Sorry I am a new one in XSL. and if i know how i can fix something like this than i would not come in this forum and ask for questions.

mhkay, I have changed somethings in that xsl before, and this is what I get. Is this right? Please help me, it is very important.

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>

<xsl:template match = "/" >
      <xsl:call-template name="statusReport">
               <xsl:with-param name="status">Gevonden</xsl:with-param>
    </xsl:call-template>
    </xsl:template>
      <xsl:template match = "/">
     <xsl:call-template name="statusReport">
     <xsl:with-param name="status">Opgelost</xsl:with-param>
    </xsl:call-template>
</xsl:template>

<xsl:template name="statusReport">
    <xsl:param name="status"></xsl:param>
    <xsl:for-each select="Issue/Status[Name=$status]">
    <Number><xsl:value-of select="Amount"/></Number>
    <string><xsl:value-of select="$status"/></string>
    </xsl:for-each>

 </xsl:template>
</xsl:stylesheet>

You now have two template rules that both say match="/". How can that possibly achieve anything?

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

okee youre right.

This is the new one now.

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>

<xsl:template match = "/" >
      <xsl:call-template name="statusReport">
               <xsl:with-param name="status">Gevonden</xsl:with-param>
    </xsl:call-template>
     <xsl:call-template name="statusReport">
     <xsl:with-param name="status">Opgelost</xsl:with-param>
    </xsl:call-template>
</xsl:template>

<xsl:template name="statusReport">
    <xsl:param name="status"></xsl:param>
    <xsl:for-each select="Issue/Status[Name=$status]">
    <Number><xsl:value-of select="Amount"/></Number>
    <string><xsl:value-of select="$status"/></string>
    </xsl:for-each>

 </xsl:template>
</xsl:stylesheet>


But how can I ever have this right?

I have the xml file:

<Issue>
     <IssueHistory_CreationDate>2004-01-01</IssueHistory_CreationDate>
      <Status>
           <Name>Find</Name>
                <Amount>28</Amount>
           <Name>resolved</Name>
                <Amount>0</Amount>
            <Name>Finished</Name>
                <Amount>0</Amount>
   </Status>
    <IssueHistory_CreationDate>2004-01-02</IssueHistory_CreationDate>
    <Status>
           <Name>Find</Name>
               <Amount>6</Amount>
          <Name>Resolved</Name>
                <Amount>6</Amount>
           <Name>Finished</Name>
                <Amount>4</Amount>
   </Status>

to this xml file
<string>Fined</string>
<Number>28</Number>
<Number>6</Number>

<string>solved</string>
<Number>0</Number>
<Number>6</Number>

<string>Finished</string>
<Number>0</Number>
<Number>4</Number>

Your code now looks more-or-less OK except that the XML says "Fined" where the XSLT says "Opgelost", and you are outputting the <string> element in the wrong place.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Hi michael,

the code is correct and i get the correct result.

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>

<xsl:template match = "/" >
      <xsl:call-template name="statusReport">
               <xsl:with-param name="status">Fined</xsl:with-param>
    </xsl:call-template>
     <xsl:call-template name="statusReport">
         <xsl:with-param name="status">Amount</xsl:with-param>
    </xsl:call-template>
</xsl:template>

<xsl:template name="statusReport">
    <xsl:param name="status"></xsl:param>
    <xsl:param name="Amount"></xsl:param>
    <String><xsl:value-of select="$status"/></String>
    <xsl:for-each select="Issue/Status[Name=$status]">
   <Number><xsl:value-of select="Amount"/></Number>
    </xsl:for-each>

 </xsl:template>
  </xsl:stylesheet>

And this is the result:

<?xml version="1.0" encoding="UTF-8"?>
<string>Fined</string>
<Number>28</Number>
<Number>6</Number>

But How can I retrieve the result of Resolved and Finished?

this is the source xml file

<Issue>
     <IssueHistory_CreationDate>2004-01-01</IssueHistory_CreationDate>
      <Status>
           <Name>Find</Name>
                <Amount>28</Amount>
           <Name>resolved</Name>
                <Amount>0</Amount>
            <Name>Finished</Name>
                <Amount>0</Amount>
   </Status>
    <IssueHistory_CreationDate>2004-01-02</IssueHistory_CreationDate>
    <Status>
           <Name>Find</Name>
               <Amount>6</Amount>
          <Name>Resolved</Name>
                <Amount>6</Amount>
           <Name>Finished</Name>
                <Amount>4</Amount>
   </Status>

youre xslt file isnt't correct, because I retrieve for the Resolved the same amount as by find.

this is youre xslt:
<xsl:template match = "/" >
      <xsl:call-template name="statusReport">
               <xsl:with-param name="status">Fined</xsl:with-param>
    </xsl:call-template>
     <xsl:call-template name="statusReport">
     <xsl:with-param name="status">Resolved</xsl:with-param>
    </xsl:call-template>
</xsl:template>

this is the result:
<string>Fined</string>
<Number>28</Number>
<Number>6</Number>
<string>Resolved</string>
<Number>28</Number>
<Number>6</Number>

I was misled by the indentation in your source document into thinking it had a different hierarchic structure.

It's not very good XML design to use a sequence such as

<name>
<amount>
<name>
<amout>
<name>
<amount>

It's better to wrap each (name, amount) pair in an enclosing element.

But if you can't change the XML, the answer is to change

    <xsl:for-each select="Issue/Status[Name=$status]">
      <Number><xsl:value-of select="Amount"/></Number>
    </xsl:for-each>

to

    <xsl:for-each select="Issue/Status/Name[.=$status]">
       <Number><xsl:value-of select="following-sibling::Amount[1]"/></Number>
    </xsl:for-each>

You'll also have to fix the fact that "resolved" is spelt two different ways in your source.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Hi Michael,

wow it's working.(Thanks a lot) Now I can see the amount of Find and Resolved. But how can I see the amount of Finished? I have now the result of Find and Resolved. and want also see the result of Finished.


I have the xml file:

<Issue>
     <IssueHistory_CreationDate>2004-01-01</IssueHistory_CreationDate>
      <Status>
           <Name>Find</Name>
                <Amount>28</Amount>
           <Name>resolved</Name>
                <Amount>0</Amount>
            <Name>Finished</Name>
                <Amount>0</Amount>
   </Status>
    <IssueHistory_CreationDate>2004-01-02</IssueHistory_CreationDate>
    <Status>
           <Name>Find</Name>
               <Amount>6</Amount>
          <Name>Resolved</Name>
                <Amount>6</Amount>
           <Name>Finished</Name>
                <Amount>4</Amount>
   </Status>

I find your questions quite extraordinary. If you can't extrapolate your current code to handle three cases rather than two, this suggests that you haven't the faintest idea how it works. Even without understanding what the instructions do, it ought to be possible to detect the pattern. Please study the code you have working, alongside an XSLT reference that explains what each instruction does, and try to understand why it works the way it does. Then you should be able to extend it.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference