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Old July 14th, 2007, 11:23 PM
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Default Client Side Processing

I am using php to call an xsl stylesheet which parses the entire xml file. All the templates I use are already parsed. I want to change what is displayed in a certain <div> based on the user clicking on links. The links contain the parameters for rendering the correct portion of the xml. I have been using asp and am converting all my sites to php. I can achieve the effect with either passing the parameter to the stylesheet. But, I want to know if the same thing is possible without any more server-side scripting, since the xml and xsl have already been sent to the client. It seems that the parameter could be modified at the client by a click that triggers "maybe" xsl:call-template and xsl:with-parameter to display the appropriate content.

Paul Hickey
 
Old July 15th, 2007, 12:06 PM
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Sorry, I haven't understood something. You seem to be describing an ASP or PHP application in which an XSLT transformation is invoked on the server. Then you say the "xml and xsl have already been sent to the client". Which is it?

Michael Kay
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Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
 
Old July 15th, 2007, 12:45 PM
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Default

Sorry about that. The xsl and xml are processed at the server using php. Now that the result has been sent to the client, is it necessary to reprocess the xml at the server just to change the contents of a <div>. I am looking at having navigation links say on the left of a web page which when clicked on change the contents of a <div> elsewhere on the page without reprocessing the tree at the server and preferably without any client side scripting. This is being done now via an xsl:parameter, e.g. and php and another round trip to the server for the same information.

given:
<site>
<menus>
<menu name="Home">
<mission>We do lots of computer stuff.
</mssion>
</menu>
<menu name="Contact Us">

<company>
<name>My Computer Services Inc.#169;</name>
<address1>123 W. Flower Blvd.</address1>
</company>
</menu>
</menus>
</site>


<div class="lsidebar" align="left">
<ul align="left"><xsl:for-each select="site/menus/menu">
<li align="left"><strong><a><xsl:attribute name="href">selectmenu.php?name=<xsl:value-of select="@name" />
</xsl:attribute><xsl:value-of select="@name" /></a></strong><br /><br /></li></xsl:for-each>
</ul></div

<div class="main"><div class="hr"></div><xsl:apply-templates select="site/menus/menu[@name=$name]" /></div>

<xsl:template match="mission">
<div class="main">
<p><xsl:apply-templates /></p>
</div>

<xsl:template match="company">
<div class="main">
<table width="50%" align="center">
<tr><td align="left"><strong><xsl:apply-templates select="name" /></strong><br /></td></tr>
<tr><td align="left"><strong><xsl:apply-templates select="address1" /></strong><br /></td></tr></table></div>
</xsl:template>

So instead so instead of a href=selectmenu.php?name=@name

is it in any way possible (without script)for it to call a different template match since I believe the information is already there. <xsl: template match="Home"> is the default displayed in <div class="main">.
I am hoping/wishing that the link could just call <xsl: template match="company"> when clicked.

Paul Hickey





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