I think he's trying to produce XSL-FO as the output from the XSLT transformation, and then use some other engine to convert the XSL-FO into RTF. But I might be wrong.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

This is the first line of my XSL

<xsl:stylesheet version="1.1"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:fo="http://www.w3.org/1999/XSL/Format"
    xmlns:func="http://exslt.org/functions"
    xmlns:exstr="http://exslt.org/strings"
    xmlns:jfor="http://www.jfor.org/xmlns/2001/stylesheet"
    xmlns:hashtable="xalan://java.util.Hashtable"
    xmlns:vector="xalan://java.util.Vector"
    xmlns:datetime="http://exslt.org/dates-and-times"
    exclude-result-prefixes="fo hashtable vector datetime"
    extension-element-prefixes="func exstr">

Michael is correct in his interpretation
I am using jfor convertor for converting XSL-FO to RTF

This is probably the wrong place to be asking XSL-FO question (and I've no idea where the right place is).

This web site however (http://www.w3schools.com/xslfo/xslfo_tables.asp) seems to indicate that the outer element for a table isn't <fo:table> but is <fo:table-and-caption>.

/- Sam Judson : Wrox Technical Editor -/

hi
I found ur posting regarding the issue in creating table inside footer
in xsl-fo
Did you get a solution for this issue.
I am facing the issue.
I would appreciate any help