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Old September 2nd, 2007, 04:33 AM
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Default captured groups with replace()

In processing text, I'm trying to convert dates of the form "January 1, 1999" or "January 1999", but I'm having trouble using captured groups. For example, I have tried to convert the dates to the form "1999-Jan" using the following:
Code:
<xsl:value-of select="replace(., '(January|February|March|April|May|June|July|August|September|October|November|December)\s+(\d{1,2},\s*)?(\d{4})(\D|$)', concat('$3', '-', substring('$1', 1, 3), '$4'), 'i')"/>
For some reason the substring() invocation doesn't work, and I have found that to be true if I call any other function, including my kti:month-from-name() function.

I'm also confused about why I need quotes around the $3 and $4.

Ian

 
Old September 2nd, 2007, 06:07 AM
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The reason for this is that what the replace function is actually performing is this:


<xsl:value-of select="replace(., '(January|February|March|April|May|June|July|Augus t|September|October|November|December)\s+(\d{1,2}, \s*)?(\d{4})(\D|$)', '$3-$1$4'), 'i')"/>

i.e. substring('$1', 1, 3) = '$1'
the substition is done after substring has been performed.

/- Sam Judson : Wrox Technical Editor -/
 
Old September 2nd, 2007, 11:07 AM
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As with any function call, the arguments to replace() are simple XPath expressions and they are evaluated independently, without any special treatment given them because they appear in a replace() call. So substring('$1', 1, 3) evaluates to '$1', just as it would anywhere, and substring($1, 1, 3) is a syntax error, just as it would be anywhere.

Try doing this with xsl:analyze-string. That will allow you to use

substring(regex-group(1), 1, 3)

Michael Kay
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Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
 
Old September 4th, 2007, 12:43 PM
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Thanks Sam and Michael!

I get it now, at least when I think about it, but I'm sure I'm going to make the same mistake again :).

As you suggested Michael, I happily got it working using <analyze-string/>.

Thanks again,
Ian






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