hello

I have an input file with the string below. I would like to get it to one long string but in a group of 4, meaning, if it is longer then 4, write a new string.
for example:

my input file is:
    <fields>
        <t id="110" class="statistic">Bytes Read1</t>
        <t id="120" class="statistic">Bytes Write2</t>
        <t id="130" class="statistic">Bytes Read3</t>
        <t id="140" class="statistic">Bytes Write4</t>
        <t id="150" class="statistic">Bytes Read5</t>
        <t id="160" class="statistic">Bytes Write6</t>
    </fields>

out put file required:
<iI31000000>Bytes Read1, Bytes Write2, Bytes Read3, Bytes Write4</iI31000000>
<iI31000001>Bytes Read5, Bytes Write6</iI3100000>

Thanks for your help
Kfir

<xsl:for-each select="t[position() mod 4 = 1]">
<iiiii>
  <xsl:for-each
     select=".|following-sibling::item[position() &lt; 4]">
     <xsl:value-of select="."/>
     <xsl:if test="position() != last()">, </xsl:if>
  </xsl:for-each>
</iiiii>
<xsl:for-each>

Packing a sequence number into your output element names seems really bad XML design so I haven't done that but, but you can do it if you really must by using <xsl:element name="iiii{position()}"> in place of <iiiii>.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Michel

thanks for your help but the solution that you gave me does not seem to work.
<xsl:for-each select="t[position() mod 4 = 1]"> - does not run on anything probably and that why it does not return an answer.
if I delete this for-each, I will recieve just one string each time for each iii (Bytes Read1) and not concatering.

try fields/t instead then...

/- Sam Judson : Wrox Technical Editor -/

If the code doesn't work then you probably integrated it incorrectly. Please show your complete code.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

according to the code you gave me, it prints the first and every 4th (meaning it will print
<iiiii>Service</iiiii>
<iiiii>Bytes Write4</iiiii>

it seems like it enter the inner for-each, but it doesnt make there anything
              <xsl:for-each select=".|following-sibling::item[position() &lt; 4]">
                 <xsl:value-of select="."/>
                 <xsl:if test="position() != last()">, </xsl:if>
              </xsl:for-each>

I am not really familiar with .|following-sibling... command, but it seems not to do there any thing. it passes after the first one, and doesnt print it as a big string from the 1st group of 4 class=statistic and so on.

thanks

input file:
<titles-en>

    <fields>
        <t id="110" class="statistic">Bytes Read1</t>
        <t id="120" class="statistic">Bytes Write2</t>
        <t id="110" class="statistic">Bytes Read3</t>
        <t id="120" class="statistic">Bytes Write4</t>
        <t id="110" class="statistic">Bytes Read5</t>
        <t id="120" class="statistic">Bytes Write6</t>
    </fields>
</titles-en>

xsl file:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="*">
    <xsl:if test = "/titles-en/fields/t/@class = 'statistic'">
        <xsl:for-each select="/titles-en/fields/t[position() mod 4 = 1]">
            <iiiii>
              <xsl:for-each select=".|following-sibling::item[position() &lt; 4]">
                 <xsl:value-of select="."/>
                 <xsl:if test="position() != last()">, </xsl:if>
              </xsl:for-each>
            </iiiii>
        </xsl:for-each>
      </xsl:if>
</xsl:template>
</xsl:stylesheet>


output:
<iiiii>Service</iiiii>
<iiiii>Bytes Write4</iiiii>

following-sibling::item should be following-sibling::t

Cut and paste error.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

thanks, but still it just print it in a different way.
out put:
<iiii1>Service, </iiii1><iiii2>Bytes Write4, </iiii2>

could it be that
<xsl:for-each select="/titles-en/fields/t[position() mod 4 = 1]">

takes only those that are mod 4, and doesnt run on the ones in between?

could it be that
<xsl:for-each select="/titles-en/fields/t[position() mod 4 = 1]">

takes only those that are mod 4, and doesnt run on the ones in between?

Sure, that's what it's supposed to do. The others are processed by the inner for-each:

<xsl:for-each select=".|following-sibling::t[position() &lt; 4]">

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference