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Old September 12th, 2007, 09:31 AM
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Default Testing for presence of a variable

Hi everyone!

I came across a little problem recently and I need to know if there's a way to solve this.

Let's say I have a style sheet called "wrapper.xsl" that imports two other stylesheets called "doSomething.xsl" and "placeHolder.xsl".

"wrapper.xsl" defines a variable named "location" which is used in "doSomething.xsl". However, due to the nature of my application, I sometimes need to use "doSomething.xsl" directly, without "wrapper.xsl".

My question is: is it possible to check for the presence of a variable in the context of "doSomething.xsl"?

I was thinking of something like this in "doSomething.xsl":

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:variable name="hasLocation">
  <xsl:choose>
   <xsl:when test="boolean($location)">
    <xsl:value-of select="true()"/>
   </xsl:when>
   <xsl:otherwise>
    <xsl:value-of select="false()"/>
   </xsl:otherwise>
  </xsl:choose>
 </xsl:variable>
 <xsl:template match="/">
  <xsl:if test="$hasLocation">

  </xsl:if>

 </xsl:template>
</xsl:stylesheet>

I don't know if there is a solution. I probably will find a workaround in the application, but still, I find this issue interesting.

Thanks,

Rushman

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Old September 12th, 2007, 09:41 AM
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Default

No, it isn't possible.

I think it's probably poor coding style to reference a variable that's defined only in an importing stylesheet, though it's legal.

I would suggest defining $location in doSomething.xsl, with some fallback value such as an empty string, and then wrapper.xsl can override it with a "real" value. This way $location will always exist and you can test whether it has been overridden by testing whether it is equal to "".

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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Old September 12th, 2007, 10:36 AM
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Thank you M. Kay, your help is always greatly appreciated.

Rushman
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