Given 2007-07-25T01:00:00-06:00

I am trying to increase the time by one hour, and then extract the hour (minus the preceeding '0')

For example,
2007-07-25T01:00:00-06:00 would return 2
2007-07-25T11:00:00-06:00 would return 12

I am receiving an error with the following regex comparison:
matches($hour,(1[0-9]|2[0-9])

Error: Arithmetic operator is not defined for arguments of types (xs:string, xs:integer)

<xsl:function name="ercot:extract-hour">

  <xsl:param name="date" as="xs:dateTime"/>
  <xsl:variable name="increase" select="$date + $one-hour"/>
  <xsl:variable name="hour"
                select="format-dateTime($increase,'[h]')"/>
  <xsl:value-of select="if (matches($hour,(1[0-9]|2[0-9]))
                           then $hour
                           else substring($hour,1,1) "/>
</xsl:function>

Well that might be because the second argument for matches needs to be a string, i.e. enclosed in single quotes.

/- Sam Judson : Wrox Technical Editor -/

As you're using XSLT 2.0 why not use the inbuilt functions? Look at creating a new dateTimeDuration of one hour and adding it to your date using the + operator. Then use hours-from-dateTime() to get the hour part.

--

Joe (Microsoft MVP - XML)