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Old January 3rd, 2008, 11:35 PM
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Default Accessing previous item in current-group() in loop

Is there a way to check the previous item in current group?

i.e.

<xsl:for-each select="current-group()">
  <xsl:if test="position() != 1">

  </xsl:if>

</xsl:for-each>

Like are there any functions that can help me achieve the item in the comment?

Cheers,
Mikey
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Old January 4th, 2008, 06:47 AM
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Default

The question applies to iteration over any sequence, except for the special case where the items in the sequence are siblings, in which case you can use preceding-sibling and following-sibling.

In general, use

<xsl:variable name="sequence" select="current-group()">
<xsl:for-each select="1 to count($sequence)">
  <xsl:variable name="position" select="."/>
  <xsl:variable name="currentItem" select="$sequence[$position]"/>
  <xsl:variable name="previousItem" select="$sequence[$position - 1]"/>

Just remember that inside the for-each, the context item (.) is a number, not a node.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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