Is there a way to check the previous item in current group?

i.e.

<xsl:for-each select="current-group()">
  <xsl:if test="position() != 1">

  </xsl:if>

</xsl:for-each>

Like are there any functions that can help me achieve the item in the comment?

Cheers,
Mikey

The question applies to iteration over any sequence, except for the special case where the items in the sequence are siblings, in which case you can use preceding-sibling and following-sibling.

In general, use

<xsl:variable name="sequence" select="current-group()">
<xsl:for-each select="1 to count($sequence)">
  <xsl:variable name="position" select="."/>
  <xsl:variable name="currentItem" select="$sequence[$position]"/>
  <xsl:variable name="previousItem" select="$sequence[$position - 1]"/>

Just remember that inside the for-each, the context item (.) is a number, not a node.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference