Delimiter for loop that may have blank rows

kwerle · November 25th, 2003, 02:57 PM

I have data that looks like this:
<parent>
<child>
  <info>bar</info>
</child>
<child>
  <data>foo</data>
  <info>bar</bar>
</child>
<child>
  <info>bar</info>
</child>
<child>
  <data>foo</data>
  <info>bar</bar>
</child>
</parent>

Really, the info nodes are more complex and have their own template.

In short, what I'd like to do is output all the data and info for any children that have a data node, with a delimiter between:
foo
bar
---
foo
bar

So I want the data, followed by the info, followed by a delimiter IF there is another child node with data. The problem is that any child node may or may not have data. This includes the first [n] children, the last [n] children, and any groups of children in the middle. I was thinking that following-sibling:: was going to solve my problem, but that fails if there is a gap anywhere but the end.

How can this be done?

TIA,
Kurt

armmarti · November 26th, 2003, 02:12 AM

(not tested)

Code:

  ...
  <xsl:template match="/">
    <xsl:apply-templates select="parent/child[data]"/>
  </xsl:template>  
 
  <xsl:template match="child[data]">
    <xsl:value-of select="data"/><br/>
    <xsl:value-of select="info"/><br/>
    <xsl:if test="following-sibling::child[data]">
      ---<br/>
    </xsl:if>
  </xsl:template>
  ...

Regards,
Armen

kwerle · November 26th, 2003, 01:25 PM

That does the trick, sure enough.

Thanks!
kwerle