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Old February 28th, 2008, 04:47 PM
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Default accessing elements using document() function


I am using the following xslt:

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions">
    <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
    <xsl:template match="/">
        <xsl:copy-of select="document('testFile.xml')"/>
        <xsl:copy-of select="document('testFile.xml')/testData/city"/>
        <xsl:value-of select="document('testFile.xml')/testData/city"/>

testFile.xml looks like this:

<testData xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://someaddress.com/">
    <city>New York</city>
    <state>New York</state>
    <country>United States</country>

the output I am getting looks like this:

<testData xmlns="http://someaddress.com/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <city>New York</city>
    <state>New York</state>
    <country>United States</country>

The problem I am having is that the second and third lines inside my xsl:template are not producing any results. When I remove the namespace declarations from testFile.xml everything works as expected. So how can I get my expected results without making any modifications to testFile.xml? Thanks

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Old February 28th, 2008, 05:49 PM
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<xsl:template match="/" xmlns:t="http://someaddress.com/">
        <xsl:copy-of select="document('testFile.xml')"/>
        <xsl:copy-of select="document('testFile.xml')/t:testData/t:city"/>
        <xsl:value-of select="document('testFile.xml')/t:testData/t:city"/>

(see the sticky post at the start of this forum for more info)

Michael Kay
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference
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Old February 28th, 2008, 07:39 PM
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Thanks. That worked!

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