How do I wrap a around text that contains ?

dhsmd · February 28th, 2008, 07:54 PM

I have some source text that is a child of the <body> tag and which has an tag in it. I want to put a around this text but XSLT puts the around the text before the and then the after the , so it is making the a child of the <body> instead of a child of the ?
Any help with this would be appreciated.

mhkay · February 28th, 2008, 08:07 PM

XSLT does whatever you ask it to. Your code is wrong, and if you show us your code then we can tell you where it is wrong.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

dhsmd · February 28th, 2008, 08:25 PM

Yes, I'm sure my approach is too simplistic but I'm keen to discover more.

My XSLT is below. What I want to do is to copy all source to the output tree but put elements around text that are children of the <body>:

<xsl:template match="/">
 <xsl:apply-templates select="descendant::td[@id='contentTD']" />
</xsl:template>

<xsl:template match="@*|node()">
 <xsl:copy>
 <xsl:apply-templates select="@*|node()" disable-output-escaping="yes"/>
 </xsl:copy>
</xsl:template>

<xsl:template match="i">
 <xsl:apply-templates />
</xsl:template>

<xsl:template match="td/text()">
 <xsl:value-of select="." />
</xsl:template>

A sample of the source document is:

<body>
this is a sentence that I really want to become HTML
</body>

and I want it to look like:

<body>
this is a sentence that I really want to become HTML
</body>

but instead I am getting:

<body>
this is a sentence that I
really
want to become HTML
</body>

Thanks for your help

samjudson · February 29th, 2008, 03:49 AM

Your xslt keeps mentioning 'td' - I see no 'td' elements in your xml, therefore I'm going to assume you're not actually showing us what your trying to do properly. We're not mind readers.

Given your example xml, this might work:

<xsl:template match="body">

<xsl:apply-templates/>

</xsl:template>

/- Sam Judson : Wrox Technical Editor -/

mhkay · February 29th, 2008, 05:36 AM

If you want a around the whole content of the body, do as Sam suggests. If you want something else, we'll need a more detailed spec of your requirements.

And get rid of that disable-output-escaping="yes". You don't need it, and it will cause the stylesheet to produce incorrect output if your data contains special characters that need to be escaped. This facility is for experts only - it's very dangerous in the hands of a beginner (and experts very rarely use it).

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

dhsmd · March 5th, 2008, 12:30 AM

Thankyou for your pointers and I appreciate the reponses. Here is a working version of my XSLT and what I am trying to achieve.

I have a collection of badly written HTML that consists of text without surrounding elements. I want to put the element around each of the paragraphs of text. What I am unable to do is cater for a sentence of text that also contains an element surrounding a word of text.

The source file has the following five lines:

<td>
 This is the first sentence
 This is a sentence with some italicized text content
 This is some final text
</td>

I want the output to be:

<td>
 
This is the first sentence
 
This is a sentence with some italicized text content
 
This is some final text
</td>

but instead I get:

<td>
 
 This is the first sentence
 
 This is a sentence with some 
 italicized
 text content
 
 This is some final text
</td>

when I apply the following XSLT:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output method="xml" omit-xml-declaration="yes" indent="yes" />
 <xsl:strip-space elements="*" />

 <xsl:template match="/">
 <xsl:apply-templates />
 </xsl:template>

 <xsl:template match="@*|node()">
 <xsl:copy>
 <xsl:apply-templates select="@*|node()"/>
 </xsl:copy>
 </xsl:template>

 <xsl:template match="i">
 <xsl:apply-templates />
 </xsl:template>

 <xsl:template match="td/text()">
 <xsl:value-of select="." />
 </xsl:template>
</xsl:stylesheet>

mhkay · March 5th, 2008, 04:52 AM

Try:

<xsl:for-each-group select="*" group-ending-with="br">
<xsl:copy-of select="current-group()"/>
 
</xsl:for-each-group>

That's XSLT 2.0 syntax, of course. In XSLT 1.0 this involves sibling recursion, which is rather more difficult, but still quite possible.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference