I have a node with a list of repetitive items:

<list>
   <name>name1</name>
   <date>date1</date>
   <name>name2</name>
   <date>date2</date>
   ...
</list>

The objective is to transform in:

<list>
   <item>
      <name>name1</name>
      <date>date1</date>
   </item>
   <item>
      <name>name2</name>
      <date>date2</date>
   </item>
   ...
</list>

I can't find a condition to iterate throw the origin xml. Any help to get me in the right direction would be appreciated.

Cheers

This is a grouping problem, solved in XSLT 2.0 by using the <xsl:for-each-group group-starting-with="name"> instruction.

In XSLT 1.0 you could use following-sibling::date[1] while looping through each name element.

/- Sam Judson : Wrox Technical Editor -/

<xsl:for-each select="name">
  <item>
    <xsl:copy-of select=".|following-sibling::date[1]"/>
  </item>
</xsl:for-each>

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Thank you for help and explanation.

Cheers