get grandchildrens position()

bonekrusher · March 19th, 2008, 09:17 AM

Hi,

I've been working on this for a few hours, I hope you can help.

I am using XSLT 1.0

Take the following XML:

Code:

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <manual>
        <gin>
            <ginwp/>
        </gin>
        <sin>
            <sinwp/>
            <sinwp/>
        </sin>
        <fin>
            <finwp/>
        </fin>
    </manual>
</root>

How would I get the position of the following elements in relation to its grandparent <manual>.

<ginwp/>
<sinwp/>
<sinwp/>
<finwp/>

Desired output would be:

1 <ginwp/>
2 <sinwp/>
3 <sinwp/>
4 <finwp/>

I've tried:
<xsl:number level="any" count="child::*" from="/root/manual"/>

But this returns a count of all descendants. e.g. (4567).

Thanks for the help,

Bones

Martin Honnen · March 19th, 2008, 09:25 AM

The following should work:

Code:

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="1.0">

  <xsl:output method="xml" indent="yes"/>

  <xsl:template match="manual">
    <results>
      <xsl:apply-templates select="*/*"/>
    </results>
  </xsl:template>

  <xsl:template match="manual/*/*">
    <xsl:number level="any" count="manual/*/*" from="manual"/>
    <xsl:copy/>
  </xsl:template>

</xsl:stylesheet>

bonekrusher · March 19th, 2008, 09:48 AM

Sweet. Thanks!