Hi,

I need to properly nest <li> .
[list]
                <li id="L_115775_tr">
                    <xref href="http://support.microsoft.com/ph/11732" id="L_115775">Windows Vista Solution Center</xref>
                    <li id="L_116381_tr">
                        <xref href="http://support.microsoft.com/ph/8722" id="L_116381">Windows Internet Explorer 7 Solution Center</xref>
                        <li id="L_125705_tr">
                            <xref href="http://support.microsoft.com/ph/1173" id="L_125705">Windows XP Solution Center</xref>
                            <li id="L_147192_tr">
                                <xref href="http://support.microsoft.com/gp/cp_email" id="L_147192">E-mail Solution Center </xref>
                                <li id="L_140164_tr">
                                    <xref href="http://support.microsoft.com/ph/8753" id="L_140164">2007 Microsoft Office Suites Solution Center</xref>
                                </li>
                            </li>
                        </li>
                    </li>
                </li>
            </ul>




To

<p>Most popular solution centers</p>
            [list]
                <li id="L_115775_tr">
                    <xref href="http://support.microsoft.com/ph/11732" id="L_115775">Windows Vista Solution Center</xref></li>
                    <li id="L_116381_tr">
                        <xref href="http://support.microsoft.com/ph/8722" id="L_116381">Windows Internet Explorer 7 Solution Center</xref></li>
                        <li id="L_125705_tr">
                            <xref href="http://support.microsoft.com/ph/1173" id="L_125705">Windows XP Solution Center</xref></li>
                            <li id="L_147192_tr">
                                <xref href="http://support.microsoft.com/gp/cp_email" id="L_147192">E-mail Solution Center </xref></li>
                                <li id="L_140164_tr">
                                    <xref href="http://support.microsoft.com/ph/8753" id="L_140164">2007 Microsoft Office Suites Solution Center</xref></li>

            </ul>

I have been trying this but not able to resolve.

It helps to show your attempt at the solution, then we can tell you where you went wrong. As it is, we can't tell whether you are a novice with no idea where to start, or an expert who overlooked a small point of detail.

It looks to me as if this can be done by

<xsl:template match="li">
  <li><xsl:copy-of select="@*|xref"/></li>
  <xsl:apply-templates select="li"/>
</xsl:template>

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

This gives the below output[list]
        <li id="L_115775_tr" />
        <li id="L_116381_tr" />
        <li id="L_125705_tr" />
        <li id="L_147192_tr" />
        <li id="L_140164_tr" />
      </ul>
the tags inside li is lost.

<li> should take all tags till starting of next <li> tag.

It works for me. You'll have to provide your exact source document and stylesheet and explain how you ran the transformation (including details of your processor).

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Actually while transformation its passing through series of xslt whic is converting the source to below
 <li id="L_116381_tr">
              <span>
                <a href="http://support.microsoft.com/ph/8722" id="L_116381">Windows Internet Explorer 7 Solution Center</a>
              </span>
              <li id="L_125705_tr">
                <span>
                  <a href="http://support.microsoft.com/ph/1173" id="L_125705">Windows XP Solution Center</a>
                </span>

So xslt should take all the nodes till starting of next <li>
but if nested ul is present [list]<li all tags[list] <li>


<li>
</li>
</li>
</ul>
<li> all tag </li>
</li>
</ul>
then it should become[list]
<li> all tags [list]
<li> all tags </li>
<li> all tags </li>
</ul>
</li>
<li> all tag </li>
</ul>

Then in my code just replace "xref" by "*" or perhaps by "node()" depending on whether you want to include child text nodes.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

I Used
<xsl:template match="li">
  <li><xsl:copy-of select="@*|node()"/></li>
  <xsl:apply-templates select="li"/>
</xsl:template>

The output contains all the <li> as shown below
 [list]
        <li id="L_115775_tr">
          <a href="http://support.microsoft.com/ph/11732" id="L_115775">Windows Vista Solution Center</a>
          <li id="L_116381_tr">
            <a href="http://support.microsoft.com/ph/8722" id="L_116381">Windows Internet Explorer 7 Solution Center</a>
            <li id="L_125705_tr">
              <a href="http://support.microsoft.com/ph/1173" id="L_125705">Windows XP Solution Center</a>
              <li id="L_147192_tr">
                <a href="http://support.microsoft.com/gp/cp_email" id="L_147192">E-mail Solution Center </a>
                <li id="L_140164_tr">
                  <a href="http://support.microsoft.com/ph/8753" id="L_140164">2007 Microsoft Office Suites Solution Center</a>
                </li>
              </li>
            </li>
          </li>
        </li>
        <li id="L_116381_tr">
          <a href="http://support.microsoft.com/ph/8722" id="L_116381">Windows Internet Explorer 7 Solution Center</a>
          <li id="L_125705_tr">
            <a href="http://support.microsoft.com/ph/1173" id="L_125705">Windows XP Solution Center</a>
            <li id="L_147192_tr">
              <a href="http://support.microsoft.com/gp/cp_email" id="L_147192">E-mail Solution Center </a>
              <li id="L_140164_tr">
                <a href="http://support.microsoft.com/ph/8753" id="L_140164">2007 Microsoft Office Suites Solution Center</a>
              </li>
            </li>
          </li>
        </li>
        <li id="L_125705_tr">
          <a href="http://support.microsoft.com/ph/1173" id="L_125705">Windows XP Solution Center</a>
          <li id="L_147192_tr">
            <a href="http://support.microsoft.com/gp/cp_email" id="L_147192">E-mail Solution Center </a>
            <li id="L_140164_tr">
              <a href="http://support.microsoft.com/ph/8753" id="L_140164">2007 Microsoft Office Suites Solution Center</a>
            </li>
          </li>
        </li>
        <li id="L_147192_tr">
          <a href="http://support.microsoft.com/gp/cp_email" id="L_147192">E-mail Solution Center </a>
          <li id="L_140164_tr">
            <a href="http://support.microsoft.com/ph/8753" id="L_140164">2007 Microsoft Office Suites Solution Center</a>
          </li>
        </li>
        <li id="L_140164_tr">
          <a href="http://support.microsoft.com/ph/8753" id="L_140164">2007 Microsoft Office Suites Solution Center</a>
        </li>
      </ul>

It doesn't feel to me as if you are trying to help yourself. I gave the solution to your original problem as stated, and you should really be able to work out how to adapt it to your revised problem without hand-holding - it you can't, then you really need to do some reading around the language.

Try apply-templates select="@* | node()[not(self::li)]"

and if that doesn't work, then please try and work out why before posting again.

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

I tried this also but its also not working Its copying only first node . To solve this I broked the problem into two parts
1. Copy the all nodes below <li>
This is working using
<xsl:template match="li">
  <li><xsl:copy-of select="@*"/>

      <xsl:apply-templates select="node()"/>


</li>
</xsl:template>
I tried using
<xsl:apply-templates select="preceding-sibling::*" />
thats not working.
Next problem is to copy till occurence of next <li>.
Here I am stuck. This is the one of issue where I am stuck.