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Old June 5th, 2008, 03:07 PM
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Default Unable to render the descriptor tag

Hello everyone.

My source document (simplified) is:

<?xml version= "1.0"?>
<?xml-stylesheet type= "text/xsl" href="file:///T:/custom/defaultss.xsl"?>
<StepsHeader>
<SentHeader>
<Sent step="1">
<?xml version= "1.0" encoding="UTF-8"?><input_data><my_input_data>xyz</my_input_data>...</input_data>
</Sent>
</SentHeader>
<ExpectedHeader>
<Expected step="1">
<?xml version= "1.0" encoding="UTF-8"?><expected_output_data><my_expected_data>123 </my_expected_data>...</expected_output_data>
</Expected>
</ExpectedHeader>
<ActualHeader>
<Actual step="1">
<?xml version= "1.0" encoding="UTF-8"?><real_output_data><the_real_data>123</the_real_data>...</real_output_data>
</Actual>
</ActualHeader>
</StepsHeader>


My current defaultss.xsl (which just highlights certain tags in the actual entry that do not match the expected) renders the XML, but for some reason all of the <?xml ver...?> tags after the first one are not being rendered. I'm guessing that I need to set up a template to handle them specifically. The actual rendering code works fine, I'm sure it's just a problem I don't understand with the template matching. I'm just not grasping what I need to modify in the following line to pick up the correct tag:

    <xsl:template match="processing-instruction()"> (this is the template that picks up the very first tag and correctly renders it)

I have tried
    <xsl:template match="*[processing-instruction()]"> (since it is a child)

    <xsl:template match="*[*[processing-instruction()]]"> (since they are actually 2 layers deep)

    <xsl:template match="*[*[*[processing-instruction()]]]"> (just for kicks)

but of course none have worked. Can someone point me in the right direction?

Thanks!
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Old June 5th, 2008, 04:24 PM
joefawcett's Avatar
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Default

The reason you can't process them is that they are XML Declarations and there should be only one at the start of the document. It looks like someone has built a large document out of smaller ones but bypassed the XML model and just treated them as text files.

--

Joe (Microsoft MVP - XML)
 
Old June 5th, 2008, 04:27 PM
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Your source document is not well-formed. I'm amazed you can get it past the XML parser, it should be rejected long before it reaches the XSLT processor. An XML declaration can appear only at the start of the file, and a processing instruction cannog have the name "xml" (See section 2.6 of the XML rec, production rule 17).

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference





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