Hello, im new working with XSL and had a question, Im having a XML shown below.
<main>
<content>
<name>A</name>
<dept>X</dept>
</content>
<content>
<name>B</name>
<dept>Y</dept>
</content>
<content>
<name>C</name>
<dept>X</dept>
</content>
<content>
<name>D</name>
<dept>Y</dept>
</content>
</main>

i want display only names who are in dept Y.
Any help from any would be gr8.
Thanks in advance

/main/content[dept='Y']/name

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Hello Michael Kay,
Thanks for your help, actually the exact XMl looks like this
<main>
    <content>
        <test>ab</test>
        <content2>
            <name>A</name>
            <dept>X</dept>
        </content2>
    </content>
    <content>
        <test>cd</test>
        <content2>
            <name>B</name>
            <dept>Y</dept>
        </content2>
    </content>
    <content>
        <test>ef</test>
        <content2>
            <name>C</name>
            <dept>X</dept>
        </content2>
    </content>
    <content>
        <test>gh</test>
        <content2>
            <name>D</name>
            <dept>Y</dept>
        </content2>
    </content>
</main>

I would like to Display
Test Name Dept
cd B Y
gh D Y

Presently im using XSL
<table>
    <tr>
        <td>Test</td>
        <td>Name</td>
        <td>Dept</td>
    </tr>
    <xsl:for-each select="main/content">
    <tr>
        <td><xsl:value-of select="test"/></td>
        <td><xsl:value-of select="content2/name"/></td>
        <td><xsl:value-of select="content2/dept"/></td>
    </tr>
    </xsl:for-each>
</table>


which prints all the nodes, as i have told i need to print nodes which dept is Y
Thanks

What part of my answer didn't you understand? It really ought to be possible to adapt the answer to a slightly different problem - if you can't do that then there's not much point giving you the answer, or you'll be back here every time the problem changes slightly.

Change the for-each to

<xsl:for-each select="main/content[content2/dept='Y']">


Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Really thanks for the Help, as im new too XSLT(just started at my work few days back), i asked you again for the help.