Hello all,

I'm new at the whole xslt thingy :)

I'm creating an xslt to format a customer's xml into a new xml format.
In the customer's xml i have a tag <start_date>20080101</start_date>.
Is it possible in xslt to transform the content of this tag into
<start_date>01/01/2008</start_date>

Thanks in advance for your help.

Greetings

Sure, take a look at the concat() and substring() functions.

<xsl:template match="start_date">
  <xsl:value-of select="concat(substring(.,8,4), '/', substring(.,3,2), '/', substring(.,1,2))"/>

(Not sure from your example whether you want dd/mm/yyyy or mm/dd/yyyy)

Michael Kay
http://www.saxonica.com/
Author, XSLT Programmer's Reference and XPath 2.0 Programmer's Reference

Hi,

Thanks for the quick reply.

Works great.

Thanks