sorting and document functions

papajimis · December 5th, 2003, 01:48 PM

Hello to all.My question is the following:I have a file that contains soem info on cds.Each cd has a position attribute that contains the file in which more information about the cd is stored. How can i sort the elements based on teh values that exist in the various xml files?i want to output xml and not xhtml by the way and i can only have one xsl file to do the transformation...The main xml file looks like this:
<case>
<cd position="cd1.xml">
...
<cd position="cd2.xml">
</case>
ANd tehn each file(cd1,2,3...xml) is like this:
<cd>
<artist>blabla</artist>
...
</cd>
I want to sort the cds by artist name.Thanks.

armmarti · December 6th, 2003, 12:19 PM

Try this (not tested):

Code:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:exsl="http://exslt.org/common">
 <xsl:template match="/">
  <xsl:variable name="all-cds">
   <xsl:for-each select="case/cd">
    <xsl:copy-of select="document(concat('cd', @position, '.xml'))/cd"/>
   </xsl:for-each>
  </xsl:variable>
 
  <sorted-by-artist>
   <xsl:for-each select="exsl:node-set($all-cds)/cd">
    <xsl:sort select="artist"/>
    <xsl:copy-of select="."/>
   </xsl:for-each> 
  </sorted-by-artist> 
 </xsl:template>
</xsl:stylesheet>

Here I think it's impossible to avoid RTF to nodeset conversion. Your XSLT processor must implement EXSLT's node-set() function or something similar.

Regards,
Armen