grouping and result-document help

mrame · October 21st, 2008, 05:00 AM

I'm using XSLT 2.0 and Saxon 9B.
I process xml files present in two directories and produce the output xml files, through result-document(). This is done by passing a parameter (<AIDtype> element value). I tried to use for-each-group, but I can't get the needed output.
For IPCC as parameter value,
1st input xml:
<?xml version="1.0" encoding="UTF-8"?>
<Section>
    <Chapter>
    <Chapter><Head>IPCC</Head>
    <test><Head>IPCC Provisioning</Head>
        <Feature>IPCC-Prov</Feature>
        <AIDType>IPCC</AIDType>
        <SectionID>0001</SectionID>
        <check cmdType = "Create"><Head></Head></check>
        <check cmdType = "Retrieve"><Head></Head></check></test>
    <test><Head>IPCC Alarm Provisioning</Head>
        <Feature>IPCC-Alarms</Feature>
        <AIDType>IPCC</AIDType>
        <SectionID>0001</SectionID>
        <check cmdType = "Set"><Head></Head></check>
        <check cmdType = "Retrieve"><Head></Head></check>
    </test></Chapter></Chapter></Section>

2nd input file:
<?xml version="1.0" encoding="UTF-8"?>
<Section><Chapter><Head>Neighbour Discovery</Head>
<Chapter><Head>IPCC</Head>
<test><Head>IPCC Provisioning</Head>
<Feature>IPCC-Prov</Feature>
<AIDType>IPCC</AIDType>
<ratttable>
<rattrow attrfield = "1">
<rattcell><TL1Commands cmdType = "Create">M</TL1Commands></rattcell>
<rattcell><TL1Commands cmdType = "Retrieve">O</TL1Commands></rattcell>
</rattrow>
</ratttable></test>
<test><Head>IPCC Provisioning</Head>
  <Feature>IPCC-Alarms</Feature>
  <AIDType>IPCC</AIDType>
  <ratttable>
   <rattrow attrfield = "1">
    <rattcell><TL1Commands cmdType = "Set">M</TL1Commands></rattcell>
    <rattcell><TL1Commands cmdType = "Retrieve">O</TL1Commands></rattcell>
   </rattrow>
  </ratttable></test>
</Chapter></Chapter></Section>

XSL:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
    <xsl:param name="repoDirectory"/>
    <xsl:param name="implDirectory"/>

    <xsl:param name="implAIDTypeTag"/>

    <xsl:output indent="yes" method="xml" version="1.1"/>

    <xsl:variable name="implSubTree" select="collection(concat($implDirectory,'/?select=*.xml'))"/>
    <xsl:variable name="repoSubTree" select="collection(concat($repoDirectory,'/?select=*.xml'))"/>

    <xsl:template match="/">
                <xsl:apply-templates select="$implSubTree//test[.//AIDType = $implAIDTypeTag]" mode="doNE"/>
    </xsl:template>

    <xsl:template match="test" mode="doNE">

        <xsl:variable name="Feature" select="Feature"/>
        <xsl:variable name="repoSection" select="$repoSubTree//test[./AIDType = $implAIDTypeTag][./Feature = $Feature]"/>
        <xsl:variable name="implSection" select="."/>
        <xsl:variable name="AIDType" select="./AIDType"/>

        <xsl:for-each-group select="check" group-by="@cmdType">
<xsl:variable name="file" select="concat(@cmdType, '-',$Feature,'.xml')"></xsl:variable>
<xsl:result-document href="{$file}">

        <xsl:apply-templates select="current-group()">
            <xsl:with-param name="repoSection" select="$repoSection"/>
            <xsl:with-param name="implSection" select="$implSection"/>
        </xsl:apply-templates>
            </xsl:result-document>
</xsl:for-each-group>
    </xsl:template>

    <xsl:template match="check">
        blah blah
    </xsl:template>

</xsl:stylesheet>

When I use the above stylesheet model, i can group by @cmdType w.r.t. <Feature>. Because of this I get two xml files, namely Retrieve-IPCC-Alarms.xml and Retrieve-IPCC-Prov.xml. I need to group all under same @cmdType.
The total output files should be Retrieve.xml, Create.xml and Set.xml only. But if I use the above type of grouping I get 4 output files. Is there any way? Any help is appreciated.

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Rummy

mhkay · October 21st, 2008, 05:09 AM

You're doing the grouping within each test element, whereas from your description (which I don't fully understand) it sounds as if you want to group across test elements. If that's the case then you clearly can't do it within a match="test" template. You need to do the for-each-group at a higher level, before processing the individual test elements.

Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer's Reference

mrame · October 21st, 2008, 11:01 PM

Thanks Mike

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Rummy