Cant get the complete nodepath of the child nodes

koenige · October 24th, 2008, 07:23 AM

<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>

<a name = "first">
 5 
 6 
 <a name = "second">
 1 
 2 
 <a name = "third">
 <a name = "four">
 3 
 </a>
 4 
 </a>
 </a>

</a>

------------------------------------------------
I want to display the values in node path hierarchy
First->one=5
First->two=6
First->second->first one = 1
First->second->second one = 2
First->second->third->four->third one = 3
First->second->third->fourth one = 4

------------------------------------------------------
test.xsl

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:for-each select="a">
 
 <xsl:value-of select="@name"/>->
 <xsl:call-template name="asearch"/>
 
</xsl:for-each>
<xsl:call-template name="bsearch"/>

<xsl:template name="asearch">

 <xsl:for-each select="a">

 <xsl:value-of select="@name"/>->
 
 <xsl:call-template name="asearch"/>
 </xsl:for-each>
 <xsl:call-template name="bsearch"/>

 </xsl:template>

 <xsl:template name="bsearch">
 <xsl:for-each select="b">
 <tr>
 <td>
 <xsl:value-of select="@name"/>
 </td>
 <td>
 <xsl:value-of select="."/>
 </td>
 </tr>
 </xsl:for-each>
 </xsl:template>

I wrote a template which yields the values .. but I cant get it in hierarchy as I mentioned before.

any help will be highly appreciated.

kind regards.
rex

Martin Honnen · October 24th, 2008, 07:50 AM

Here is a sample XSLT 1.0 stylesheet:

Code:

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="1.0">

  <xsl:output method="html" indent="yes"/>

  <xsl:template match="/">
    <html lang="en">
      <head>
        <title>Example</title>
      </head>
      <body>
       [list]
          <xsl:for-each select="*/descendant::*[@name and not(*)]">
            <li>
              <xsl:for-each select="ancestor::*">
                <xsl:value-of select="concat(@name, '->')"/>
              </xsl:for-each>
              <xsl:value-of select="concat(@name, ' = ', .)"/>
            </li>
          </xsl:for-each>
        </ul>
      </body>
    </html>
  </xsl:template>

</xsl:stylesheet>

When run against your sample input it outputs the following HTML document:

Code:

<html lang="en">
   <head>
      <meta http-equiv="Content-Type" content="text/html; charset=utf-8">

      <title>Example</title>
   </head>
   <body>
      [list]
         <li>first-&gt;one =  5 </li>
         <li>first-&gt;two =  6 </li>
         <li>first-&gt;second-&gt;first one =  1 </li>
         <li>first-&gt;second-&gt;second one =  2 </li>
         <li>first-&gt;second-&gt;third-&gt;four-&gt;third one =  3 </li>
         <li>first-&gt;second-&gt;third-&gt;fourth one =  4 </li>
      </ul>
   </body>
</html>

--
Martin Honnen
Microsoft MVP - XML

koenige · October 24th, 2008, 08:21 AM

Thanks martin for your quick reply.

I learned a bit of ancestor and descendats here. Thanks.

Another question. How can I restrict the ancestors ( sample xml file is a basic one.. I have more complicated original one )..

Lets say .. tags from a->b->c->d->e->f=5 ... I want like from d->e->f=5

Thank you once again.

Martin Honnen · October 24th, 2008, 08:32 AM

I am not sure I understand what you want to achieve now.
Assuming you want to process only 'd' and 'e' ancestor elements you could use

Code:

<xsl:for-each select="ancestor::*[self::d or self::e]">

--
Martin Honnen
Microsoft MVP - XML

koenige · October 24th, 2008, 08:37 AM

What I meant was ..
I dont want to write upto the root .. sondern ..
only upto specific tags.

lets say the hierarchy...-> root->tag1->tag2->tag3->tag4->tag5->value=5
I want it from tag4->tag5->value=5

previous code writes completely ..

I will try the 'self' method and let u know ..

thanks

koenige · October 24th, 2008, 09:16 AM

ancestor with self not working for this task.

So I tried a workaround ( i am c++ guy)

Code:

    <xsl:variable name="temp" select="boolean(false)"/>
    <xsl:for-each select="ancestor::*">
    <xsl:if test="boolean($temp) = boolean(true)">
       <xsl:value-of select="concat(@name, '::')"/>
    </xsl:if>                            
    <xsl:if test="@name = 'tag3'">                            
       <xsl:value-of  select="$temp = boolean(true)"/>
        </xsl:if>
     </xsl:for-each>

but I dont know how to declare a variable .. that is $temp to set as false .. and when the loop reaches the tag3, I set it as true .. so from Tag4.. it will display the result I wanted ..
But my if condition failed.

Martin Honnen · October 24th, 2008, 09:53 AM

Maybe you want

Code:

<xsl:for-each select="ancestor::*[@name = 'tag3' or @name = 'tag4']">

--
Martin Honnen
Microsoft MVP - XML

koenige · October 24th, 2008, 10:08 AM

That also not fetching the answer..

I might have confused u ..

The thing is .. I know only 'Tag3'- name,after that- others(Tag4 & Tag5) I dont know ..

I believe, the workaround will work fine ..
but I dont know how to assign a value to a variable or change it to check it in if statement.

sorry to bug u mate.

Martin Honnen · October 24th, 2008, 10:16 AM

I think you will need to show us the XML you have and explain clearly how you want to identify the nodes you want to output, then we should be able to solve the problem with XSLT and XPath.
Otherwise we can only guess, last guess:

Code:

<xsl:for-each select="ancestor::*[@name = 'tag3' or ancestor::*/@name = 'tag3']">

--
Martin Honnen
Microsoft MVP - XML

koenige · October 24th, 2008, 10:20 AM

Thank you martin for help and time.

Code:

<xsl:for-each select="ancestor::*">    
 <xsl:variable name= "icount" select="position()"/>                         <xsl:if test="$icount &gt; 5">

This workaround works.

I will try ur method now.

anyway .. Thanks for ur time and effort