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Old October 28th, 2008, 01:35 PM
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Default help - EXSLT func cannot set more than one result!


I tried to execute the following xsl generated by contivo tool and executed in web methods environment.

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet version="1.0"
     extension-element-prefixes="func ctvf"

  <xsl:variable name='_root' select='/'/>
  <xsl:template match='/'>
        <xsl:value-of select="ctvf:testForNullNumber($_root/Source[1]/textfield[1], &quot;&quot;)"/>

  <func:function name="ctvf:testForNullNumber">
    <xsl:param name="node"/>
    <xsl:param name="defaultValue"/>
      <xsl:when test="local-name($node) = ''">
        <func:result select="$defaultValue"/>
      <xsl:when test="string-length(normalize-space(string($node))) = 0">
        <func:result select="$defaultValue"/>
        <func:result select="number($node)"/>


when i run the xsl in wm i get the following error.

com.wm.app.b2b.server.ServiceException: com.wm.pkg.xslt.util.LocalizedTransformerException : [XSL.0002.9002] JAXP: Error during transformation - javax.xml.transform.TransformerException: An EXSLT function cannot set more than one result!

why is that so?

Old October 28th, 2008, 02:17 PM
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I think that question needs to be asked on a forum specific to the XSLT processor you are using. The fine details of how EXSL functions are implemented are likely to vary from one processor to another.

Michael Kay
Author, XSLT 2.0 and XPath 2.0 Programmer's Reference

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