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Old January 9th, 2009, 11:44 PM
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Default Regarding xml-html transformation of an xml string using xslt and javascript

Hi,

I am trying to transform an XML string to HTML page using xslt. But I am getting the following exception :

The stylesheet doesn't contain a document element. The stylesheet may be empty, or it may not be a well-formed XML document. My code is as below :

Test.html
----------------

<html>
<head>
<script>
function loadXMLDoc(fname)
{
var xmlDoc;
// code for IE
if (window.ActiveXObject)
{
xmlDoc=new ActiveXObject("Microsoft.XMLDOM");
}
// code for Mozilla, Firefox, Opera, etc.
else if (document.implementation&& document.implementation.createDocument)
{

xmlDoc=document.implementation.createDocument(""," ",null);
}
else
{
alert('Your browser cannot handle this script');
}


xmlDoc.async=false;
xmlDoc.loadXML(fname);
alert("mozilla document");
return(xmlDoc);
}

function displayResult()
{
alert("suprakash ");

xmlString = "<catalog><cd><title>Empire Burlesque</title><artist>Bob Dylan</artist></cd></catalog>";
alert("suprakash mozilla 1");
xml=loadXMLDoc(xmlString);
alert("suprkash mozilla 2");
xsl=loadXMLDoc("C:\\xmlXslt\\cdCatalog.xsl");
// code for IE
alert("suprakash mozilla 3");
if (xsl.parseError.errorCode != 0) {
error = xsl.parseError;
alert("Error parsing XSLT file:\n" + error.reason + "[" + error.url +
": line " + error.line + ", col " + error.linepos + "]");
}
alert("suprakash 1");
if (window.ActiveXObject)
{
alert("suprakash 2");
ex = xml.transformNode(xsl);
alert("suprakash 3 " + ex );
}
// code for Mozilla, Firefox, Opera, etc.
else if (document.implementation && document.implementation.createDocument)
{
xsltProcessor=new XSLTProcessor();
xsltProcessor.importStylesheet(xsl);
resultDocument = xsltProcessor.transformToFragment(xml,document);
document.getElementById("example").appendChild(res ultDocument);
alert(document.getElementById("example"));
}
}
</script>
</head>
<body id="example" onLoad="displayResult()">
</body>
</html>

cdcatalog.xls
--------------------

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<h2>My CD Collection</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th align="left">Title</th>
<th align="left">Artist</th>
</tr>
<xsl:for-each select="catalog/cd">
<tr>
<td><xsl:value-of select="title"/></td>
<td><xsl:value-of select="artist"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>

Awaiting for an early response.

Regards

Suprakash
 
Old January 12th, 2009, 01:23 AM
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Join Date: Jun 2008
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Default

Try to google for the exception "The stylesheet doesn't contain a document element. The stylesheet may be empty, or it may not be a well-formed XML document.". You can find solution.
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