Default Namespace

iceandrews · February 5th, 2009, 05:37 PM

I'm curious if there's a method in XSLT to get the default namespace of the input document.

I have a situation where I need to get the default namespace of the input document, but the root element node MIGHT be in a prefixed alternate namespace.

If the root element node was IN the default namespace always, I could use something like the following:

Code:

<xsl:template match="/">
    <xsl:value-of select="/*:MYELEMENTNAME/namespace-uri(.)" />
</xsl:template>

Unfortunately, that it's just a work around the real problem. When I have the root element in a prefixed-namespace, the above code obviously does not get the default namespace. I need to be able to get the default namespace when I have a document structure like the following:

Code:

<foo:ROOT xmlns:foo="http://foo.bar" xmlns="http://defaultns.com">
    <CHILD>
         <Description>Data</Description>
    </CHILD>
</foo:ROOT>

In this case, I'm not sure how to directly retrieve the default namespace.

Thanks!

mhkay · February 5th, 2009, 06:07 PM

string(/*/namespace::*[name()=''])

iceandrews · February 6th, 2009, 04:42 PM

Quote:

Originally Posted by mhkay

string(/*/namespace::*[name()=''])

Yeah that'll do it.

I also figured out you can use this as well:

Code:

namespace-uri-for-prefix('',/*:ROOTELEMENT)