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Old February 10th, 2009, 04:08 PM
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Default how to read xml files doing select="document()" ?

Here is my sample xml

<?xml version="1.0"?>
<abc:testNews xmlns:rcdc="http://abc.com" xmlns:xhtml="http://www.w3.org/1999/xhtml" xmlns:xf="http://www.w3.org/2002/xforms" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:ev="http://www.w3.org/2001/xml-events" xmlns:chiba="http://chiba.sourceforge.net/xforms">

press1.xml and press2.xml have same structure for example.
<title>News One </title>
<intro> This is introduction</intro>

Here is my XSL

<xsl:stylesheet version="2.0" xmlns:xhtml="http://www.w3.org/1999/xhtml" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:abc="http://abc.com" xmlns:fn="http://www.w3.org/2005/02/xpath-functions" xmlns:exsl="http://exslt.org/common" exclude-result-prefixes="xhtml">
<xsl:template match="/">
<xsl:for-each select="//abc:pressRelease">
<xsl:value-of select="abc:newsXMLPath"/>
<xsl:variable name="xmlpath" select="document('abc:newsXMLPath')"/>

This is an incomplete XSL. basically I am trying to print the Title of each news. News1 and news2.xml. Am I doing this wrong? What do I need to do in order to first get the xml location and than loop through to get the value of each title for news1 and news2.?
Old February 10th, 2009, 04:51 PM
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You want something like

<xsl:for-each select="//abc:pressRelease">
<xsl:value-of select="document(abc:newsXMLPath)/news/title"/>
Michael Kay
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference
Old February 10th, 2009, 05:08 PM
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Awesome that worked. U are great mhkay.

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