Here is my sample xml

<?xml version="1.0"?>
<abc:testNews xmlns:rcdc="http://abc.com" xmlns:xhtml="http://www.w3.org/1999/xhtml" xmlns:xf="http://www.w3.org/2002/xforms" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:ev="http://www.w3.org/2001/xml-events" xmlns:chiba="http://chiba.sourceforge.net/xforms">
<abc:pageDetails>
<abc:year>2007</abc:year>
<abc:pressRelease>
<abc:newsXMLPath>/press1.xml</abc:newsXMLPath>
</abc:pressRelease>
<abc:pressRelease>
<abc:newsXMLPath>/press2.xml</abc:newsXMLPath>
</abc:pressRelease>
</abc:pageDetails>
</abc:testNews>

press1.xml and press2.xml have same structure for example.
<news>
<title>News One </title>
<intro> This is introduction</intro>
</news>

Here is my XSL

<xsl:stylesheet version="2.0" xmlns:xhtml="http://www.w3.org/1999/xhtml" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:abc="http://abc.com" xmlns:fn="http://www.w3.org/2005/02/xpath-functions" xmlns:exsl="http://exslt.org/common" exclude-result-prefixes="xhtml">
<xsl:template match="/">
<xsl:for-each select="//abc:pressRelease">
<xsl:value-of select="abc:newsXMLPath"/>
</xsl:for-each>
<xsl:variable name="xmlpath" select="document('abc:newsXMLPath')"/>
</xsl:template>
</xsl:stylesheet>

This is an incomplete XSL. basically I am trying to print the Title of each news. News1 and news2.xml. Am I doing this wrong? What do I need to do in order to first get the xml location and than loop through to get the value of each title for news1 and news2.?

You want something like

<xsl:for-each select="//abc:pressRelease">
<xsl:value-of select="document(abc:newsXMLPath)/news/title"/>
</xsl:for-each>

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

Awesome that worked. U are great mhkay.