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March 6th, 2009, 01:55 AM
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regex-group problem in XSLT
dear sir
input:==>
<link linkend="b10" type="bib"><emph type="italic">The handbook of English linguistics</emph> Sless Tarjat Penman 2001</link>
output:==>
The handbook of English linguistics Sless Tarjat Penman <xref ref-type="bibr" xlink:href="ref010">2001</xref>
expected output:==>
<emphasis type="italic">The handbook of English linguistics</emphasis> Sless Tarjat Penman <xref ref-type="bibr" xlink:href="ref010">2001</xref>
and i have written XSLT as follows:
<xsl:template match="link[@type='bib']">
<xsl:variable name="year" select="."/>
<xsl:analyze-string select="$year" regex="\s*(.*?\s*\w*)\s*(\d{{4}})\s*(\w*\s*.*?)">
<xsl:matching-substring>
<xsl:value-of select="regex-group(1)"/>
<xsl:element name="xref">
<xsl:attribute name="ref-type">bibr</xsl:attribute>
<xsl:choose>
<xsl:when test="string-length($bslt)=1">
<xsl:attribute name="xlink:href" namespace="href">ref00<xsl:value-of select="$bslt"/></xsl:attribute>
</xsl:when>
<xsl:when test="string-length($bslt)=2">
<xsl:attribute name="xlink:href" namespace="href">ref0<xsl:value-of select="$bslt"/></xsl:attribute>
</xsl:when>
<xsl:otherwise>
<xsl:attribute name="xlink:href" namespace="href">ref<xsl:value-of select="$bslt"/></xsl:attribute>
</xsl:otherwise>
</xsl:choose>
<xsl:value-of select="regex-group(2)"/>
<xsl:value-of select="regex-group(3)"/>
</xsl:element>)
</xsl:matching-substring>
</xsl:analyze-string>
</xsl:template>
<xsl:template match="emph[@type='italic']">
<xsl:element name="emphasis">
<xsl:attribute name="type">italic</xsl:attribute>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
and i am not getting the required output what will be the problem?
please help me
thanks & regards
Rajashekhara
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March 6th, 2009, 02:45 AM
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Try this:
Code:
<xsl:template match="link[@type='bib']">
<xsl:variable name="year" select="text()"/>
<xsl:variable name="bslt" select=" substring-after(@linkend, 'b')"/>
<xsl:variable name="name" select="$bslt"></xsl:variable>
<xsl:apply-templates select="emph"></xsl:apply-templates>
<xsl:analyze-string select="text()[2]" regex="(\s)(.*)(\d{{4}})\s*(\w*\s*.*?)">
<xsl:matching-substring>
<xsl:value-of select="regex-group(1)"/>
<xsl:value-of select="regex-group(2)"/>
<xsl:element name="xref">
<xsl:attribute name="ref-type">bibr</xsl:attribute>
<xsl:choose>
<xsl:when test="string-length($name)=1">
<xsl:attribute name="xlink:href" namespace="href">ref00<xsl:value-of select="$bslt"/></xsl:attribute>
</xsl:when>
<xsl:when test="string-length($name)=2">
<xsl:attribute name="xlink:href" namespace="href">ref0<xsl:value-of select="$bslt"/></xsl:attribute>
</xsl:when>
<xsl:otherwise>
<xsl:attribute name="xlink:href" namespace="href">ref<xsl:value-of select="$bslt"/></xsl:attribute>
</xsl:otherwise>
</xsl:choose>
<xsl:value-of select="regex-group(3)"/>
<xsl:value-of select="regex-group(4)"/>
</xsl:element>
</xsl:matching-substring>
</xsl:analyze-string>
</xsl:template>
<xsl:template match="emph[@type='italic']">
<emphasis type="italic">
<xsl:value-of select="."></xsl:value-of>
</emphasis>
</xsl:template>
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Rummy
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March 6th, 2009, 03:01 AM
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no its not working,
i think, actual problem with
<xsl:value-of select="regex-group(1)"/>
for that its not converting any tags which are inside the <link> tag
thanks & regards
Rajashekhara
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March 6th, 2009, 03:06 AM
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Did you try with the code I posted? I have changed your code. Copy and past my code and then check again. The regex-group(1) in my code just selects the space.
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Rummy
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March 6th, 2009, 03:13 AM
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ok that is not my question.
<xsl:analyze-string select="$year" regex="(\s)(.*)(\d{{4}})\s*(\w*\s*.*?">
in this
"
<xsl:value-of select="regex-group(2)"/> " is selecting only text not any tags
thanks & regards
Rajashekhara
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March 6th, 2009, 03:20 AM
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Yes it wont select any tags as I have selected the text (" Sless Tarjat Penman 2001") part thro' analyze-string. I have referenced the <emph> tag using apply-templates. So the regex-group(1) will select the space, second group will select the text and third will select the year. Is it clear?
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Rummy
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March 6th, 2009, 03:22 AM
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i want to select text as well as tags, what to do for that
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March 6th, 2009, 04:10 AM
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In your code the variable $year will give the ouput "
The handbook of English linguistics Sless Tarjat Penman 2001". So this text is only processed.
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Rummy
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March 6th, 2009, 04:14 AM
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no, my input is
<link linkend="b10" type="bib"><emph type="italic">The handbook of English linguistics</emph> Sless Tarjat Penman 2001</link>
and i want output like this
<emphasis type="italic">The handbook of English linguistics</emphasis> Sless Tarjat Penman <xref ref-type="bibr" xlink:href="ref010">2001</xref>
thanks & regards
Rajashekhara
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March 6th, 2009, 04:28 AM
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Friend of Wrox
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Join Date: Jun 2008
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Try this:
Code:
<xsl:template match="link[@type='bib']">
<xsl:variable name="year" select="text()"/>
<xsl:variable name="bslt" select=" substring-after(@linkend, 'b')"/>
<xsl:variable name="name" select="$bslt"></xsl:variable>
<xsl:apply-templates select="emph"></xsl:apply-templates>
<xsl:analyze-string select="text()" regex="(\s)(.*)(\d{{4}})\s*(\w*\s*.*?)">
<xsl:matching-substring>
<xsl:value-of select="regex-group(1)"/>
<xsl:value-of select="regex-group(2)"/>
<xsl:element name="xref">
<xsl:attribute name="ref-type">bibr</xsl:attribute>
<xsl:choose>
<xsl:when test="string-length($name)=1">
<xsl:attribute name="xlink:href" namespace="href">ref00<xsl:value-of select="$bslt"/></xsl:attribute>
</xsl:when>
<xsl:when test="string-length($name)=2">
<xsl:attribute name="xlink:href" namespace="href">ref0<xsl:value-of select="$bslt"/></xsl:attribute>
</xsl:when>
<xsl:otherwise>
<xsl:attribute name="xlink:href" namespace="href">ref<xsl:value-of select="$bslt"/></xsl:attribute>
</xsl:otherwise>
</xsl:choose>
<xsl:value-of select="regex-group(3)"/>
<xsl:value-of select="regex-group(4)"/>
</xsl:element>
</xsl:matching-substring>
</xsl:analyze-string>
</xsl:template>
<xsl:template match="emph[@type='italic']">
<emphasis type="italic">
<xsl:value-of select="."></xsl:value-of>
</emphasis>
</xsl:template>
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