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Old March 26th, 2009, 06:28 AM
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Default XSLT Variable output

I'm using XSLT 2.0 and Oxygen editor with Saxon 9B.

When I use the below template to the input <syntax> element, I get the output &lt;AID&gt;. Why don't I get the <test> element in the output? Any element given inside a variable cannot be printed. Is there any way to do it?

My XML snippet is shown below:

<Syntax>SET‑ATTR‑EQPT:[&lt;TID>]:&lt;AID>:&lt;CTAG>::[&lt;NTFCNCDE>],&lt;CONDTYPE>,[&lt;LOCN>],[&lt;DIRN>],,[&lt;SRVEFF>];</Syntax>

My template is :

<xsl:template match="Syntax">
<xsl:variable name="cmdSyntax">
<xsl:analyze-string select="." regex="^.*?:.*?:(.*?):.*$">
<xsl:matching-substring>
<test>
<xsl:value-of select="regex-group(1)"/>
</test>
</xsl:matching-substring>
</xsl:analyze-string>
</xsl:variable>
<xsl:value-of select="$cmdSyntax"></xsl:value-of>
</xsl:template>

My output is :

&lt;AID&gt;

Required output is :

<test>&lt;AID&gt;</test>

thanks in advance,
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Old March 26th, 2009, 06:45 AM
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Default

The xsl:value-of instruction flattens its operand to a text node. You probably want xsl:copy-of.
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Old March 26th, 2009, 06:51 AM
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Thanks a lot Michael. It worked.
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