hi ,

i was trying to convert a xml file into fixed length text file using XSLT, iam having problems with ampersand.i could convert '&' to & and handle it but its printing out & instead of '&' into text file ,how can i handle this i.e write out & into text file.

i tried disable-output-escaping="yes" but its not working properly for me

Thanks

Are you using xsl:output method="text"?

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

yes iam using <xsl:output method="text"/>

In that case you will have to explain in more detail what you are doing. Please post a minimal example that demonstrates the problem, and tell us how you are running it.

If you are serializing using method="text" then there should never be any XML escaping in the output, so you're obviously doing something wrong and we need to see what.

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

iam converting a xml file which is generated by normal text file write's through code. there iam changing all '&'s to &amp; and writing into file.

ex:
<Rows>
<Row>
<Data>
<Value>example &amp; something</Value>
</Data>
<Data>
<Value>this is test</Value>
</Data>
</Row>
<Row>
<Data>
<Value>tst23</Value>
</Data>
</Row>
<Rows>

xslt:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" >
<xsl:output method="text"/>
<xsl:template match="*">
<xsl:value-of select="normalize-space(.)"/>
</xsl:template>

<xsl:template match="/">
<xsl:apply-templates select="Rows"/>
</xsl:template>

<xsl:template match="Rows">
<xsl:apply-templates select="Row">
</xsl:apply-templates>
</xsl:template>

<xsl:template match="Row">
<xsl:apply-templates select="Data">
</xsl:apply-templates>
</xsl:template>

<xsl:template match = "Data">
<xsl:call-template name="manipulate-string">
<xsl:with-param name="value" select="Value"/>
</xsl:call-template>
</xsl:template>

<xsl:template name="manipulate-string">
<xsl:param name="value"/>
<xsl:value-of select="$value"/>
</xsl:template>

</xsl:stylesheet>

iam doing something like above but with more string and other manipulations.am having problems with ampersand etc.

thank you

OK, thanks. The other half of the question was: how are you running the transformation? (What processor? Client side or server side? What API calls from your application?)

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

i use LIBXSLT and LIBXML in ruby code as shown below and its server side.

stylesheet_doc = LibXML::XML::Document.file('xsl_file.xsl')
stylesheet = LibXSLT::XSLT::Stylesheet.new(stylesheet_doc)

xml_doc = LibXML::XML::Document.file('temp_test.xml')
result = stylesheet.apply(xml_doc);

thanks

Thanks. I'm afraid I don't know libxslt and ruby well enough to help.

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

I am also not familiar with libXML and libXSLT and Ruby but the API docs suggest that the result of the apply method is an libXML XML document. I don't know what they do in the case of output method="text" but for instance the Mozilla XSLT API, when output method="text", gives you the text as the text contents of the root element of the result document so with your libXML you might want to check whether
gives you the plain text you are looking for. That is just a guess however, you might have better chances finding someone with knowledge of the those APIs on a Ruby list (or a list dedicated to those libraries).

__________________
Martin Honnen
Microsoft MVP (XML, Data Platform Development) 2005/04 - 2013/03
My blog

Thanks for your reply's ,i will look around for some ruby forums.