Cals table to Html table XSLT

ROCXY · May 11th, 2009, 06:56 AM

Dear All,

I am looking for a XSLT to include into my current XSL for conversion of cals table to html table set.

I tried using following link: which result with following errors.

http://www.biglist.com/lists/xsl-lis.../msg00666.html

Error Message:
SystemID: file.xsl
Location: 205:0
Description: XPath syntax error at char 69 on line 205 in {...pec[@colname=$namest]/@col ...}:
Unexpected token name "num" beyond end of expression
URL: http://www.w3.org/TR/xpath20/#ERRXPST0003

Any help would be appreciable.

Martin Honnen · May 11th, 2009, 07:04 AM

I think the post you copied the XSLT from has unwanted line breaks so change lines like

Code:

    <xsl:variable name="colst"
select="ancestor::*[colspec/@colname=$namest]/colspec[@colname=$namest]/@col
num"/>
    <xsl:variable name="colend"
select="ancestor::*[colspec/@colname=$nameend]/colspec[@colname=$nameend]/@c
olnum"/>

to

Code:

    <xsl:variable name="colst"
select="ancestor::*[colspec/@colname=$namest]/colspec[@colname=$namest]/@colnum"/>
    <xsl:variable name="colend"
select="ancestor::*[colspec/@colname=$nameend]/colspec[@colname=$nameend]/@colnum"/>

and the errors should go away.

ROCXY · May 12th, 2009, 06:04 AM

Dear Martin,

Thank U so much - Working fine.

roozy · July 13th, 2010, 11:30 AM

Dear ROCXY/ Martin,

I'm an XSLT newbie an have an urgent need to transform CALS tables to XHTML, So I used the XSLT discussed above. However, I don't know what is it that I'm doing wrong cuz when I transfer a table like:

Code:

<article xmlns='http://docbook.org/ns/docbook'>
        <tgroup cols='5' align='left' colsep='1' rowsep='1'>
            <colspec colname='c1'/>
            <colspec colname='c2'/>
            <colspec colname='c3'/>
            <colspec colnum='5' colname='c5'/>
            <thead>
                <row>
                    <entry namest="c1" nameend="c2" align="center">Horizontal Span</entry>
                    <entry>a3</entry>
                    <entry>a4</entry>
                    <entry>a5</entry>
                </row>
            </thead>
            <tfoot>
                <row>
                    <entry>f1</entry>
                    <entry>f2</entry>
                    <entry>f3</entry>
                    <entry>f4</entry>
                    <entry>f5</entry>
                </row>
            </tfoot>
            <tbody>
                <row>
                    <entry>b1</entry>
                    <entry>b2</entry>
                    <entry>b3</entry>
                    <entry>b4</entry>
                    <entry morerows='1' valign='middle'><para>Vertical Span</para></entry>
                </row>
                <row>
                    <entry>c1</entry>
                    <entry namest="c2" nameend="c3" align='center' morerows='1' valign='bottom'>Span Both</entry>
                    <entry>c4</entry>
                </row>
                <row>
                    <entry>d1</entry>
                    <entry>d4</entry>
                    <entry>d5</entry>
                </row>
            </tbody>
        </tgroup>
</article>

I get this:

Code:

    
        Sample CALS Table
            
                
                    Horizontal Span
                    a3
                    a4
                    a5
                
                    f1
                    f2
                    f3
                    f4
                    f5
                
                    b1
                    b2
                    b3
                    b4
                    Vertical Span
                
                
                    c1
                    Span Both
                    c4
                
                
                    d1
                    d4
                    d5

where I was expecting to get the equivalent XHTML table. I'd appreciate if you could help me out and I apologize in advance if I'm doing something really stupid

Roozy

mhkay · July 13th, 2010, 11:38 AM

I would guess a namespace issue. Check that the XSLT code is looking for elements in the namespace where your instance has them.

Martin Honnen · July 13th, 2010, 11:42 AM

If you use an XSLT 2.0 processor like Saxon or AltovaXML tools then I think that stylesheet you are trying to use could be easily adapted by using
version="2.0"
and
xpath-default-namespace="http://docbook.org/ns/docbook"
on the xsl:stylesheet element.

roozy · July 13th, 2010, 11:56 AM

its always the namespace issue, isn't it ?

Thanks allot guys,