Extracting second chlid element of same parent node using following-sibling

ROCXY · May 22nd, 2009, 08:22 AM

Hi All,

I am trying to pull the second and other following child element 'p' from the parent element 'fn' keeping the first element 'p' as is; but it result in repetition of same child element values.

Input XML

<fn>
Line1
Line2
Line3
</fn>

Used XSLT:

<xsl:template match="//fn">
<xsl:choose>
<xsl:when test="p[following-sibling::p]">
<block>
<xsl:apply-templates/>
</block>
</xsl:when>
</xsl:choose>
<xsl:apply-templates/>
</xsl:template>

Required Ouput:

<fn>
Line1
<block>Line2</block>
<block>Line3</block>
</fn>

Any help would be grateful.

Martin Honnen · May 22nd, 2009, 08:32 AM

I don't understand your verbal description but the following templates should give you the posted required output:

Code:

  <xsl:template match="fn | fn/p[1]">
    <xsl:copy>
      <xsl:apply-templates/>
    </xsl:copy>
  </xsl:template>
  
  <xsl:template match="fn/p[position() &gt; 1]">
    <block>
      <xsl:apply-templates/>
    </block>
  </xsl:template>

samjudson · May 22nd, 2009, 08:33 AM

It all depends on how you want to pick the children elements. There are many ways to do this - the way you have used equates to stating "select all 'p' elements that have a 'p' element following them" - i.e. it will select all apart from the last one - exactly what you don't want.

Far better to simply use the position() xpath function:

Code:

<xsl:template match="fn">
  <fn><xsl:apply-templates/></fn>
</xsl:template>
<xsl:template match="p[1]">
  <p><xsl:apply-templates/></p>
</xsl:template>
<xsl:template match="p[position() > 1]">
  <block><xsl:apply-templates/></block>
</xsl:template>

mhkay · May 22nd, 2009, 10:56 AM

I think I would do:

Code:

<xsl:template match="p[1]">
  <xsl:copy-of select="."/>
</xsl:template>

<xsl:template match="p">
  <block><xsl:copy-of select="child::node()"/></block>
</xsl:template>