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  #1 (permalink)  
Old August 14th, 2009, 09:35 AM
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Default parse multiple .XSD files with XSLT

Hi!
I have a problem with solving this problem,
i have 5 XSD Files (SCHEMA) where i want to get all <documentation> elements from and write them in one new XML File.
How can i do that ?
My problem is that i dont have any XML file which initialises the XSLT File...
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Old August 14th, 2009, 10:08 AM
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With XSLT 2.0 you can run a named template as the initial template:
Code:
<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:xs="http://www.w3.org/2001/XMLSchema"
  version="2.0">

  <xsl:template name="main">
     <root>
       <xsl:copy-of select="(document('schema1.xsd'), document('schema2.xsd'), document('schema3.xsd'), document('schema4.xsd'), document('schema5.xsd'))//xs:documentation"/>
     </root>
   </xsl:template>

</xsl:stylesheet>
You can then run your stylesheet with your XSLT processor and designate the template with name 'main' as the initial template, for instance with option -it:main for Saxon and its command line usage.
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Old August 15th, 2009, 06:48 AM
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okay so far ive already been,
i did it with <xslt:variable name="file" select="doc('schema.xsd')">

i dont understand how to run that XSLT without an real input XML ...
In my Browser he needs an XML for it,
and Eclipse Oxygen parser wants an XML to...
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Old August 15th, 2009, 07:28 AM
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As I said, with XSLT 2.0 you do not need a primary input document, you can instead define a named template and start processing with that named template.
With Saxon there is a command line option -it:templatename you can use, with AltovaXML tools you can use a command line option /n templatename so for the stylesheet I posted you would use e.g.
altova.exe /xslt2 sheet.xsl /n main
with Saxon something like
java -jar dir/saxon9.jar -xsl:sheet.xsl -it:main

I am not familiar with Eclipse or Oxygen, ask in a forum dedicated to that software if you don't find a setting yourself.


If you use XSLT 1.0 then you do not have that option, in that case you either need to provide a dummy XML input or you can choose one of the schema documents as the primary input document.
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Old August 15th, 2009, 07:36 AM
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ah okay now i know what youre talking about! BiG THANXXX
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Old August 17th, 2009, 08:24 AM
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i tried it with <xsl:copy-of select="doc('filename.xsd')//documentation"/>
but it won't work ...

<xsl:copy-of select="doc('filename.xsd')//text()"/> does work....

whhhyyy ??
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Old August 17th, 2009, 08:28 AM
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Well the elements are in the namespace http://www.w3.org/2001/XMLSchema so bind a prefix to that namespace and use the prefix, as I did in my sample:
Code:
<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:xs="http://www.w3.org/2001/XMLSchema"
  version="2.0">

  <xsl:template name="main">
     <root>
       <xsl:copy-of select="(document('schema1.xsd'), document('schema2.xsd'), document('schema3.xsd'), document('schema4.xsd'), document('schema5.xsd'))//xs:documentation"/>
     </root>
   </xsl:template>

</xsl:stylesheet>
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  #8 (permalink)  
Old August 17th, 2009, 08:32 AM
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Martin wrote ...//xs:documentation, so why did you expect ...//documentation to work? The element is in a namespace, so like all elements in a namespace, the name must be prefixed in an XPath expression.
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Old August 17th, 2009, 09:58 AM
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Okay, seems like i didnt understand that basic thing.. i hopefully do now!

first i had this Namespace:
Code:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns="http://www.w3.org/2001/XMLSchema"
    version="2.0">
so i thought //documentation shall work ..

now i use
Code:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xmlns="http://www.w3.org/2001/XMLSchema"
    version="2.0">
so i dont have to mark all xml elements with "xs:", right?
any other suggestions for it ?? Or is there an error in reasoning again ?

here is now my working "make documentation xml" xslt code:
Code:
<xsl:template match="filelist">
                <documentations>
                    <xsl:for-each select="file">
                        <xsl:if test="doc-available(text())">
                            <xsl:variable name="data" select="doc(text())"/>
                            <xsl:for-each select="$data//node()/@name">
                                    <documentation>
                                        <name><xsl:value-of select="."/></name>
                                        <text><xsl:value-of select="parent::node()[//xs:documentation]"/></text>
                                    </documentation>
                            </xsl:for-each>
                        </xsl:if>
                    </xsl:for-each>
                </documentations>
</xsl:template>
with the input XML:
Code:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="create_doc_XML.xsl" ?>
<filelist>
    <file>sourceData.xsd</file>
    <file>test-cases.xsd</file>
    <file>uoms.xsd</file>
</filelist>
i thought taking this xml with filenames would be a good way to make this program more dynamic..

now JUDGEMENT plz

by the way you guys are GREAT! big THANX

Last edited by chaostimmy; August 17th, 2009 at 10:01 AM..
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Old August 17th, 2009, 10:02 AM
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No, the default namespace in the stylesheet does not apply to unprefixed names in XPath expressions.

You can set a default namespaces for such names in XSLT 2.0 using the default-xpath-namespace attribute.
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