Parameter value in If condition

Hari7 · November 11th, 2009, 10:40 AM

Hi All,

How can i use parameter value in if condtion in place of boolean value 'And/Or'

I am trying like below:

Code:

 <xsl:template match="summary">
        <xsl:param name="field1"></xsl:param>
        <xsl:param name="field2"></xsl:param>
        <xsl:param name="boolean"></xsl:param>
        
        <xsl:if test="@keyword=$field1  $boolean @keyword=$field2">            
            
           <xsl:value-of select="summary"></xsl:value-of> 
        </xsl:if>
    </xsl:template>

I want to use ' $boolean' in if condition.

Thanks
Hari

Martin Honnen · November 11th, 2009, 10:48 AM

'and' and 'or' are not boolean values, they are boolean operators. You can't use a variable with the name of an 'operator' in the place of an operator, not with XPath and not usually with other programming languages, unless they have some 'eval' function.

So unless you use an extension function that allows you to evaluate a string you construct at run-time as an XPath expression you can't do what you want.

Saxon 9 has http://www.saxonica.com/documentatio.../evaluate.html

mhkay · November 11th, 2009, 11:46 AM

An interesting variation on the common theme of "I want to construct an XPath expression as a string at run-time". You can do that with extensions such as saxon:evaluate(), but not with standard XSLT.

However, since there are only two variations here, you could do

Code:

test="($op='and' and @keyword=$field1 and @keyword=$field2) or
    ($op='or' and (@keyword=$field1 or @keyword=$field2))"