applying an attribute to children value while copying

dexter62 · November 24th, 2009, 11:17 AM

Hi,

Suppose we were having:

<group shared="true">
<element name="a" type="xsd:string" shared="false"/>
<element name="b" type="xsd:string" shared="false"/>
</group>
<element name="c" type="xsd:string" shared="false"/>

which should be come:

<element name="a" type="xsd:string" shared="true"/>
<element name="b" type="xsd:string" shared="true"/>
<element name="c" type="xsd:string" shared="false"/>

In other words, the group/@shared takes precedence over the same child attribute and is removed from the output. How to go about this in XSLT 1.1?
Hope I am not being too ignorant here, feels like a really easy problem...

mhkay · November 24th, 2009, 11:32 AM

Firstly, XSLT 1.1 doesn't exist. It was withdrawn quite a while ago. (Yes, there's boilerplate text on this forum that refers to it! It's obsolete too...)

This one's quite easy (in XSLT 1.0)

Code:

<xsl:template match="group/element">
  <xsl:copy>
     <xsl:copy-of select="@type|@name|../@shared"/>
  </xsl:copy>
</xsl:template>
<xsl:template match="element">
  <xsl:copy-of select="."/>
</xsl:template>