Problem in replacing XML namespace using XSLT

kris13 · December 17th, 2009, 05:15 AM

Hello,

I need to just replace the XML namespace using XSLT. My input XML looks like as follows. I just want to replace "oldNameSpace" with "newNameSpace" and rest of XML want as it is..

Code:

<?xml version="1.0" encoding="UTF-8"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"
	xmlns:impl="oldNameSpace" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
	<soapenv:Body>
		<impl:requestData
			xmlns:impl="oldNameSpace">
			<xmlString ChangeDate="2008-12-18T14:47:11.773+01:00"
				IdentificationNumber="WDDKJ5GBXAF000229"
				OrderNumber="08 295 70821"
				ProductionNumber="1700158">
				<ServiceTool ExecutionTime="2008-12-18T14:47:11.773+01:00"
					UserID="kris" Version="1.1.1" />
			</xmlString>
		</impl:requestData>
	</soapenv:Body>
</soapenv:Envelope>

I tried with following XSL

Code:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
	xmlns:source="oldNameSpace" xmlns:desti="newNameSPace" xmlns="newNameSPace"
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.0">
	<xsl:output method="xml" encoding="iso-8859-1" indent="yes" />


	<xsl:template match="source:*">
		<xsl:element name="{name()}" namespace="newNameSPace">
			<xsl:apply-templates select="@*|node()" />
		</xsl:element>
	</xsl:template>

	<xsl:template match="@*|node()">
		<xsl:copy>
			<xsl:apply-templates select="@*|node()" />
		</xsl:copy>
	</xsl:template>
</xsl:stylesheet>

but it is not giving the desired results...it is giving the following results.

Code:

<?xml version="1.0" encoding="iso-8859-1"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:impl="oldNameSpace" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
	<soapenv:Body>
		<impl:requestData xmlns:impl="newNameSPace">
			<xmlString xmlns:impl="oldNameSpace" ChangeDate="2008-12-18T14:47:11.773+01:00" IdentificationNumber="WDDKJ5GBXAF000229" OrderNumber="08 295 70821" ProductionNumber="1700158">
				<ServiceTool ExecutionTime="2008-12-18T14:47:11.773+01:00" UserID="kris" Version="1.1.1"/>
			</xmlString>
		</impl:requestData>
	</soapenv:Body>
</soapenv:Envelope>

problem with the above is that -- "<xmlString xmlns:impl="oldNameSpace" is still showing the "oldNameSpace" only.. where as there was no namespace for that element in the input

Anyone can help in this ....
Thanks a lot.

---Krishna

mhkay · December 17th, 2009, 05:51 AM

<xsl:copy> copies the element and all its in-scope namespaces. In XSLT 2.0 you can use <xsl:copy copy-namespaces="no"> to suppress this. In XSLT 1.0 you will have to use <xsl:element> rather than <xsl:copy>.

kris13 · December 17th, 2009, 06:48 AM

Thanks Michael !

I tried to use that also.. xsl:copy copy-namespaces="no"> and version- 2.0

but result is same... :(

if you observe the tranformed result
transformation is adding this "oldNameSpace" addtionally...how should i get rid of this...
<xmlString xmlns:impl="oldNameSpace" ......................

---Krishna

mhkay · December 17th, 2009, 07:34 AM

Which XSLT 2.0 processor did you use?

(People sometimes make the mistake of just adding version="2.0" to the stylesheet and then running it through an XSLT 1.0 processor. This will simply cause the 1.0 processor to ignore the attributes it doesn't understand).

kris13 · December 17th, 2009, 07:58 AM

I am using the following Java Code to transform the input file

Code:

File xmlFile = new File("./xml_xsl/input.xml");
		File xsltFile = new File("./xml_xsl/transform.xsl");

		// JAXP reads data using the Source interface
		Source xmlSource = new StreamSource(xmlFile);
		Source xsltSource = new StreamSource(xsltFile);

		// the factory pattern supports different XSLT processors
		TransformerFactory transFact = TransformerFactory.newInstance();
		Transformer trans = null;
		try {
			trans = transFact.newTransformer(xsltSource);
			File f = new File("./xml_xsl/output.xml");
			trans.transform(xmlSource, new StreamResult(f));
		} catch (TransformerConfigurationException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		} catch (TransformerException e) {
			// TODO Auto-generated catch block
			e.printStackTrace();
		}

mhkay · December 17th, 2009, 08:16 AM

If you have Saxon on your classpath this code will pick up an XSLT 2.0 processor; if you don't, it will load the default XSLT processor from the JDK, which is a 1.0 processor (Xalan).

kris13 · December 18th, 2009, 01:41 AM

Hello Micheal,,,,

Thanks for your reply.
following is the classes used for transformation----
class com.sun.org.apache.xalan.internal.xsltc.trax.Trans formerFactoryImpl
class com.sun.org.apache.xalan.internal.xsltc.trax.Trans formerImpl
--------------------------------------------------------------------
Now i have modified the XSL as below:

Code:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
	xmlns:source="oldNameSpace" 
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.0">
	<xsl:output method="xml" encoding="iso-8859-1" indent="yes" />
	<xsl:template match="source:*">
		<xsl:element name="{local-name()}" namespace="newNameSPace">
			<xsl:apply-templates select="@* | node()" />
		</xsl:element>
	</xsl:template>
	<xsl:template match="@*|node()">
		<xsl:copy copy-namespaces="no">
			<xsl:apply-templates select="@*|node()" />
		</xsl:copy>
	</xsl:template>

It gives me new namespace for the "impl:requestData"
replaced nameSpace...and no prefix on the "xmlString" element ....but i ended into different problem....

Now I also need to put the prefix on <xmlString> element but not on the children of <xmlString> ......

So finally i need an output xml like this....

Code:

<?xml version="1.0" encoding="iso-8859-1"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:impl="oldNameSpace" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
	<soapenv:Body>
		<impl:requestData xmlns:impl="newNameSPace">
			<impl:xmlString xmlns:impl="oldNameSpace" ChangeDate="2008-12-18T14:47:11.773+01:00" IdentificationNumber="WDDKJ5GBXAF000229" OrderNumber="08 295 70821" ProductionNumber="1700158">
				<ServiceTool ExecutionTime="2008-12-18T14:47:11.773+01:00" UserID="kris" Version="1.1.1"/>
			</impl:xmlString>
		</impl:requestData>
	</soapenv:Body>
</soapenv:Envelope>

it would be great if you can help in this...

samjudson · December 18th, 2009, 04:20 AM

Just add the following:

<xsl:template match="xmlString">
<impl:xmlString>
<xsl:apply-templates select="@* | node()" />
</impl:xmlString>
</xsl:template>

kris13 · December 18th, 2009, 05:01 AM

Hello Sam,

The template is working...but in addition it adding one attribute to one of
child element, i have highlighted that

<impl:requestData xmlns:impl="newNameSPace">
<impl:xmlString xmlns:impl="oldNameSpace" ChangeDate="2008-12-18T14:47:11.773+01:00" IdentificationNumber="WDDKJ5GBXAF000229" OrderNumber="08 295 70821" ProductionNumber="1700158">
<ServiceTool xmlns:impl="oldNameSpace" ExecutionTime="2008-12-18T14:47:11.773+01:00" UserID="kris" Version="1.1.1"/>
</impl:xmlString>
</impl:requestData>

I think this will create while validation of XML.

samjudson · December 18th, 2009, 05:12 AM

I don't know why whatever XSLT/XML processor you are using keeps redefining the Impl prefix, but I'm happy to let you know that it doesn't matter.

Also, not sure which namespace you want the xmlString to be in (old or new) but you should have all the tools to make any further changes you need.

Let us know if you need any more help.