Reconstruct XML using XSLT in Tree View

nisargmca · December 31st, 2009, 07:26 AM

Hi there,

I have following XML and i want to transform it to my desire XML using XSLT ,i have succeded somewhat but not whole problem is solved .So
I need help

Given is My Input XML

<?xml version = '1.0'?>
<ROWSET>
<irp_account num="1">
<IRP_CARRIER_ID_NUMBER>274845</IRP_CARRIER_ID_NUMBER>
<IRP_ACCOUNT_NUMBER>55002</IRP_ACCOUNT_NUMBER>
</irp_account>
<irp_account num="83">
<IRP_CARRIER_ID_NUMBER>928265</IRP_CARRIER_ID_NUMBER>
<IRP_ACCOUNT_NUMBER>59897</IRP_ACCOUNT_NUMBER>
<NAME_TYPE>LG</NAME_TYPE>
<NAME>LAMBERT TRUCKING INC</NAME>
<ADDRESS_TYPE>PH</ADDRESS_TYPE>
</irp_account>
<irp_account num="97">
<IRP_CARRIER_ID_NUMBER>957858</IRP_CARRIER_ID_NUMBER>
<IRP_ACCOUNT_NUMBER>59940</IRP_ACCOUNT_NUMBER>
<NAME_TYPE>LG</NAME_TYPE>
<NAME>SONNY DAVIS INC</NAME>
<ADDRESS_TYPE>MA</ADDRESS_TYPE>
</irp_account>
<irp_account num="98">
<IRP_CARRIER_ID_NUMBER>957858</IRP_CARRIER_ID_NUMBER>
<IRP_ACCOUNT_NUMBER>59940</IRP_ACCOUNT_NUMBER>
<NAME_TYPE>LG</NAME_TYPE>
<NAME>SONNY DAVIS INC</NAME>
<ADDRESS_TYPE>PH</ADDRESS_TYPE>
</irp_account>
</ROWSET>

With the use of XSLT i want to generate Output XML like this.

<?xml version="1.0"?>
<T0020>
<IRP_ACCOUNT>
<IRP_CARRIER_ID_NUMBER>274845</IRP_CARRIER_ID_NUMBER>
<IRP_ACCOUNT_NUMBER>55002</IRP_ACCOUNT_NUMBER>
<IRP_NAME>
<NAME_TYPE>LG</NAME_TYPE>
<NAME>A P SUPPLY CO</NAME>
<IRP_ADDRESS>
<ADDRESS_TYPE>PH</ADDRESS_TYPE>
</IRP_ADDRESS>
<IRP_ADDRESS>
<ADDRESS_TYPE>MA</ADDRESS_TYPE>
</IRP_ADDRESS>
</IRP_NAME>
</IRP_ACCOUNT>
</T0020>

I have tried below XSLT but it is not giving desire result

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/ROWSET">
<xsl:element name="T0020">
<xsl:apply-templates select="irp_account"/>
</xsl:element>
</xsl:template>
<xsl:template match="irp_account">
<xsl:element name="IRP_ACCOUNT">
<xsl:apply-templates select="IRP_CARRIER_ID_NUMBER"/>
<xsl:apply-templates select="IRP_ACCOUNT_NUMBER"/>
<xsl:apply-templates select="IRP_ACCOUNT_TYPE"/>
<xsl:apply-templates select="NAME_TYPE"/>
<xsl:apply-templates select="ADDRESS_TYPE"/>
</xsl:element>
</xsl:template>
<xsl:template match="IRP_CARRIER_ID_NUMBER">
<xsl:copy-of select="descendant-or-self::IRP_CARRIER_ID_NUMBER"/>
</xsl:template>
<xsl:template match="IRP_ACCOUNT_NUMBER">
<xsl:copy-of select="descendant-or-self::IRP_ACCOUNT_NUMBER"/>
</xsl:template>
<xsl:template match="IRP_ACCOUNT_TYPE">
<xsl:copy-of select="descendant-or-self::IRP_ACCOUNT_TYPE"/>
</xsl:template>
<xsl:template match="NAME_TYPE">
<xsl:element name="IRP_NAME">
<xsl:copy-of select="descendant-or-self::NAME_TYPE"/>
<xsl:copy-of select="following-sibling::NAME"/>
</xsl:element>
</xsl:template>
<xsl:template match="ADDRESS_TYPE">
<xsl:element name="IRP_ADDRESS">
<xsl:copy-of select="descendant-or-self::ADDRESS_TYPE"/>
<xsl:copy-of select="following-sibling::NAME"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

Please help ....

Martin Honnen · December 31st, 2009, 07:36 AM

The input sample you posted has four 'irp_account' elements, the result sample you posted has only one 'IRP_ACCOUNT' element. Do you want to only process the first 'irp_account' element? Or is the result sample not complete?

nisargmca · December 31st, 2009, 08:02 AM

No this one is only sample in input XML i just want to show that there my be a
chance that Address type for a particular IRP_ACCOUNT may be PH(Physical Address) or both (Physical and Mailing).

I have shown desired Output XML as only one element to save space.

Thanks Martin Honnen for your reply..

mhkay · December 31st, 2009, 08:21 AM

Try something like this:

Code:

  <xsl:template match="irp_account">
    <IRP_ACCOUNT>
        <xsl:apply-templates select="IRP_CARRIER_ID_NUMBER"/>
        <xsl:apply-templates select="IRP_ACCOUNT_NUMBER"/>
        <IRP_NAME>
          <xsl:apply-templates select="IRP_ACCOUNT_TYPE"/>
          <xsl:apply-templates select="NAME_TYPE"/>    
          <xsl:apply-templates select="ADDRESS_TYPE"/>
        </IRP_NAME>
    </IRP_ACCOUNT>    
  </xsl:template>

  <xsl:template match="NAME_TYPE">    
     <xsl:copy-of select="."/>
  </xsl:template>

  <xsl:template match="NAME">    
     <xsl:copy-of select="."/>
  </xsl:template>

  <xsl:template match="ADDRESS_TYPE">
    <IRP_ADDRESS>    
        <xsl:copy-of select="."/>
    </IRP_ADDRESS>
   </xsl:template>

The templates that you have written like this:

Code:

   <xsl:template match="IRP_CARRIER_ID_NUMBER">
     <xsl:copy-of select="descendant-or-self::IRP_CARRIER_ID_NUMBER"/>
   </xsl:template>

aren't wrong, but they had me very confused: it would be much clearer to write <xsl:copy-of select="."/>. Alternatively, you could use the "identity template" pattern where the default template for all elements is

[code]
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
[/copy]

and then only override this when you want to do something other than copy the element unchanged.

Martin Honnen · December 31st, 2009, 08:23 AM

Well usually if you want to transform XML to XML and you present an input sample and an output sample then the output sample should be exactly what you want to produce from the input sample presented.
Otherwise it is not clear what you want to achieve.
If you want to map 'irp_account' in the input XML to 'IRP_ACCOUNT' elements in the output XML then that is easy to achieve and with less verbosity than you have:
[code
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">

<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:template match="ROWSET">
<T0020>
<xsl:apply-templates/>
</T0020>
</xsl:template>

<xsl:template match="irp_account">
<IRP_ACCOUNT>
<xsl:copy-of select="IRP_CARRIER_ID_NUMBER | IRP_ACCOUNT_NUMBER"/>
</IRP_ACCOUNT>
</xsl:template>

</xsl:stylesheet>
[/code]
I am afraid I can't tell where, for instance for the first 'irp_account' element, you would get the output elements like 'NAME' or 'NAME_TYPE' from.