I have lot of html tags in my xml (well formated) which i need to transform to html using xsl. I am using xsl-copy-of function to copy and display it as is.Everything is working fine, but now i got a problem. I want to remove a string "/mydomain.com" from all image src tags.

ie. <img src="/mydomain.com/Global/Images/test.jpg" />

This should become

<img src="/Global/Images/test.jpg" />

for all img src tags /mydomain.com should be replaced.

I googled and read like using xsl-copy-of we cannot do the replacement. I need to use identity template or so.I dont have much idea, i am not an xsl expert, so can anyone solve the problem for me?


My XML
__________

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<root>
<content>
<h1>Hai</h1>
<br />
<img src="/mydomain.com/Global/Images/test.jpg" />
</content>
</root>

test.xsl
__________

<?xml version="1.0" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes" />
<xsl:template match="/">
<div>
<xsl:copy-of select="root/content"/>
</div>
</xsl:template>
</xsl:stylesheet>

You can use the substring-after function.

__________________
Joe
http://joe.fawcett.name/

You need two template rules. One that processes the img/@src attributes:

<xsl:template match="img/@src">
<xsl:attribute name="src">
<xsl:value-of select="substring-after(@src)"/>
</xsl:attribute>
</xsl:template>

and the other processes everything else:

<xsl:template match="*|@node()">
<xsl:copy>
<xsl:apply-templates select="*|@node()"/>
</xsl:copy>
</xsl:template>

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

I tried to make changes as you suggested, but not seem to be working, can you please check what i am doing wrong?

I want to copy all HTML contents only under root/content and transform it through XSL to produce HTML code.

My XML
__________

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<root>
<content>
<h1>Hai</h1>
<br />
<img src="/mydomain.com/Global/Images/test.jpg" />
</content>
</root>

test.xsl
__________

<?xml version="1.0" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes" />
<xsl:template match="/">
<div>
<xsl:template match="img/@src">
<xsl:attribute name="src">
<xsl:value-of select="substring-after(@src,'mydomain.com')"/>
</xsl:attribute>
</xsl:template>
<xsl:template match="*|@node()">
<xsl:copy>
<xsl:apply-templates select="*|@node()"/>
</xsl:copy>
</xsl:template>
</div>
</xsl:template>
</xsl:stylesheet>

Sorry, it should be substring-after(., 'mydomain.com')

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

Change your code like the one below:

__________________
Rummy

I tried to implement the above code , it worked fine in some cases

But when ever image tag had some other attributes before src its not working

eg: <img height="100" align="left" width="10" src="/ifc.org/en_US/Global/Images/new.jpg" />


This is not working

<img src="/ifc.org/en_US/Global/Images/new.jpg" /> this is working!!!

Any one can help?

This is what i have used


<xsl:template match="*|@node()">
<xsl:copy>
<xsl:apply-templates select="*|@node()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="img/@src">
<xsl:attribute name="src">
<xsl:value-of select="substring-after(.,'mydomain.com')"/>
</xsl:attribute>
</xsl:template>