Create & update global var

ismailc · January 21st, 2010, 05:15 AM

Good day,

I created a variable, But when i want to use it at another place to check the value of the variable. I get the error: "variable created outside of scope."

Code:

<xsl:variable name="VenExpand" select="Attributes/Attribute[ @name='visible']" />

How do i create a Global var on top & then anywhere give it a value, so that i can use it throughout.

Regards

samjudson · January 21st, 2010, 05:24 AM

You can never 'change' the value of a variable in XSLT, as it is a functional language.

You can declare a global variable fine by defining it outside of any template and then refer to it inside any template, you just can't 'update' its value.

Try explaining the problem you are trying to solve, rather than how you are trying to solve it and we may be able to offer an alternative.

ismailc · January 21st, 2010, 05:36 AM

Hi, I would like to display a table based on whether an object is visible.

The object is being loaded on the foreach & the table is outside the foreach.
I can set the var when i'm in the foreach. But after the foreach when i want to check if i have to show the table the var is outisde it's scope.

Code:

<xsl:for-each ..
   <xsl:call-templatename="CreateObject">
         <xsl:if test="@name='VE10IntVendorFields'">
            <xsl:variable name="VenEx" select="Attributes/Attribute[ @name='visible']" />
          ....
</xsl:for-each>
 
<xsl:if test="$VenEx = 'True'"> 
  <table>

I hope this help... Please help

samjudson · January 21st, 2010, 05:45 AM

You'll just have to work out how to refer to that item in your XML without being inside the for-each loop.

I don't know what your input XML looks like and you missed the select attribute for the for-each instruction so this is just a guess, but something like this:

Code:

<xsl:variable name="VenEx" select="Object[@name='VE10IntVendorFields']/Attributes/Attribute[@name='visible']"/>

<xsl:if test="$VenEx='True'">
...
</xsl:if>

ismailc · January 21st, 2010, 06:20 AM

I'm editing the xslt file & it's a 3rd party application (site) searched & can't find the xml files.

Please help, i still get the error: "VarEn is either not defined or outside of scope"

Code:

<!-- First do all the ungrouped objects -->
<xsl:for-eachselect="Activity/ObjectGroup[@type='default']/Object">
<xsl:sortselect="@index"data-type="number" />
<xsl:variablename="index"select="@index" />
<xsl:variablename="nextNode"select="../Object[ @index > $index ][1]" />

<xsl:variablename="VenEx"select="Object[@name='VE10IntVendorFields']/Attributes/Attribute[@name='visible']"/>
 
</xsl:for-each>

 
 
<xsl:iftest="$VenEx = 'True'"> 
  <table>

samjudson · January 21st, 2010, 06:30 AM

Your <xsl:variable> instruction CANNOT go INSIDE the <xsl:for-each> instruction, otherwise it will not exist once you get out of it.

Imagine in a C# program if you wrote the following:

Code:

function Method1()
{
   int i = 10;
   Method2();
}

function Method2()
{
   Console.WriteLine("i = " + i); // This will not compile - i does not exist in Method2().
}

The same is true in XSLT - if you declare the variable inside the <xsl:for-each> instruction it doesn't exist anywhere apart from inside that instruction.

Code:

<xsl:for-each>
...
</xsl:for-each>

<xsl:variable name="VenEx" select="Activity/ObjectGroup[@type='default']/Object[@name='VE10IntVendorFields']/Attributes/Attribute[@name='visible']"/>

<xsl:if test="$VenEx = 'True'">
   <table>
    ...
    </table>
</xsl:if>

Also, and we have mentioned this more than once now - please try to paste your code so that it retains the spaces in your XML markup - trying to read or test your code is hard enough as it is without the extra work.

ismailc · January 21st, 2010, 08:12 AM

Thank You for the explenation - it makes sense

I dont get any errors now but I cant get my var value i don't thinks it sets a value, I dont see the table :(

the var i define here has a vlue of "true"

Code:

<xsl:for-eachselect="Activity/ObjectGroup[@type='default']/Object">
<xsl:sortselect="@index"data-type="number" />
<xsl:variablename="index"select="@index" />
<xsl:variablename="nextNode"select="../Object[ @index > $index ][1]" />
<xsl:variablename="nextCol"select="$nextNode/@columnNo" />
<xsl:variablename="vis"select="string(Attributes/Attribute[ @name='visible'])" />
<xsl:variablename="visNextCol"select="string($nextNode/Attributes/Attribute[ @name='visible'])" />
<xsl:call-templatename="CreateObject"><xsl:with-paramname="Object"select="." /></xsl:call-template>
 
<xsl:if test="@name='VE1077Doc'">
<xsl:variablename="VenExpand"select="Attributes/Attribute[ @name='visible']" />
<xsl:value-ofselect="$VenExpand" />
</xsl:if>
 
</xsl:for-each>

Here i can't seem to set the value or check the value of var

Code:

<xsl:variablename="VenEx"select="Object[@name='VE1077Doc']/Attributes/Attribute[ @name='visible']"/>
<xsl:value-ofselect="$VenEx" />
<xsl:if test="$VenEx = 'True'"> 
   <table>

samjudson · January 21st, 2010, 08:20 AM

Without seeing your input XML its almost impossible to answer, seeing as how you are doing some complicated sorting and stuff inside the for-each loop.

If you don't know what XML this XSLT file is processing then can I suggest you ask someone who does know, because without an example XML to process you're not going to get very far.

ismailc · January 21st, 2010, 08:34 AM

Thank You for helping

ismailc · January 21st, 2010, 03:26 PM

Thank You Samjudson

I finally got it going, it took me a while i tried to read the xslt file's code & played a bit.
Working on your code & a lot of trying this & that I got it.

Code:

 
<xsl:variablename="VenEx2"select="Activity/ObjectGroup[@type='default']/Object[@name='VE1077Doc']/Attributes/Attribute[@name='visible']" />

<xsl:value-ofselect="$VenEx2" />