<xsl:copy-of> with <xsl:element>

learningxsl · February 4th, 2010, 01:02 PM

I need to make a deep copy of a node in my source document and add a prefix to the element name in the output document, for example:

Source:

Code:

<stuffidon'twanttocopy>
<level1>
<level2>"text"</level2>
<level2>"text">
<level3>"more text"</level3>
</level2>
</level1>
</stuffidon'twanttocopy>

Desired output:

Code:

<prefix:level1>
<prefix:level2>"text"</prefix:level2>
<prefix:level2>"text">
<prefix:level3>"more text"</prefix:level3>
</prefix:level2>
</prefix:level1>

I've tried constructing a template using <xsl:copy-of> in combination with <xsl:element> without success. Can anyone suggest a sample template so I get the syntax right?

Martin Honnen · February 4th, 2010, 01:07 PM

Code:

<xsl:template match="*">
  <xsl:element name="prefix:{local-name()}" namespace="http://example.com/">
     <xsl:apply-templates/>
  </xsl:element>
</xsl:template>

<xsl:template match="stuffidontwanttocopy">
  <xsl:apply-templates/>
</xsl:template>

learningxsl · February 4th, 2010, 03:42 PM

Martin: Many thanks, it's almost working now! I still have trouble excluding <stuffIdontwanttocopy>, though--can't find the right match pattern.

If my source document looks like this:

Code:

<root>
<stuff1>
<nestedstuff1/>
<nestedstuff2/>
</stuff1>
<stuff2:this is the only node I want to keep>
<nestedstuff1/>
<nestedstuff2/>
</stuff2>
<stuff3>
<nestedstuff1/>
<nestedstuff2/>
</stuff3>
</root>

then how do I phrase the match attribute in the second template to strip out everything but <stuff2> and its subelements?

Code:

<xsl:template match="*">
  <xsl:element name="prefix:{local-name()}" namespace="http://example.com/">
     <xsl:apply-templates/>
  </xsl:element>
</xsl:template>

<xsl:template match="???">
  <xsl:apply-templates/>
</xsl:template>

samjudson · February 4th, 2010, 05:07 PM

If you don't want to keep an element, or anything in it, then do this:

<xsl:template match="stuff1" />

If you want to keep the stuff inside it, but not the element itself, then do this:

<xsl:template match="stuff2">
<xsl:apply-templates select="*"/>
</xsl:template>

learningxsl · February 4th, 2010, 05:27 PM

I want to keep <stuff2> with all its children, attributes and content. However, if I do

Code:

<xsl:template match="stuff1" />

I get rid of <stuff1> only, not the root element which is its parent and not its descendants either. Of course I can't match on the root element because then I don't get the child node I want to keep, either.

Thanks as always.

samjudson · February 4th, 2010, 05:36 PM

I'm not 100% clear on what you are expecting your output to look like. I'm guessing your real XML doesn't have elements called stuff1 etc.

Any chance of some real input XML, and what you are expecting your output to look like.

learningxsl · February 4th, 2010, 05:58 PM

Sam,

you're right, I was trying to simplify.

My input XML looks like this:

Code:

<?xml version="1.0" encoding="UTF-8"?>

<ead>    
    <eadheader>
        <eadid>ID Number</eadid>
        <filedesc>
            <titlestmt>
                <titleproper>Title, <date
                    type="inclusive">Inclusive Date</date> (bulk <date
                        type="bulk">Bulk Date</date>) </titleproper>
            </titlestmt>   
        </filedesc>
        <profiledesc>
            <creation>Created by Somebody.</creation>
            <langusage>Written in <language encodinganalog="dc:language" langcode="eng"
                >English</language>. </langusage>
        </profiledesc>
    </eadheader>
    <archdesc>
        <did>
            <head>Summary Information</head>
            <unitid>Call Number</unitid>
            <repository label="Location: ">
                <corpname>Repository Name</corpname>
                <subarea>Name Line 2</subarea>
                <subarea>Name Line 3</subarea>
                <address>
                    <addressline>Address Line 1 </addressline>
                    <addressline>Address Line 2</addressline>
                </address>
            </repository>
            <unittitle label="Title and dates: ">Title
                <unitdate type="inclusive"
                    >Inclusive Date</unitdate> (bulk <unitdate 
                        type="bulk">Bulk Date</unitdate>) </unittitle>
            <physdesc label="Size: ">
                <extent >Extent Statement</extent>
            </physdesc>
            <origination label="Creator: ">
                <persname >Creator's Name
                 </persname>
            </origination>
            <langmaterial label="Language(s) of material: ">
                <language langcode="eng">English</language>. Other languages include <language langcode="fre"
                    >French</language>. </langmaterial>
            <abstract label="Abstract: ">Abstract here.</abstract>
            <physloc label="Storage note:">Storage note here.</physloc>
        </did>
    </archdesc>
</ead>

My desired output is only one child node, with only some of its descendants, and all of the element names changed to include a prefix:

Code:

<ead:did>
    <ead:head>Summary Information</ead:head>
    <ead:unitid>Call Number</ead:unitid>
    <ead:unittitle label="Title and dates: ">Title
        <ead:unitdate type="inclusive"
            >Inclusive Date</ead:unitdate> (bulk <ead:unitdate 
                        type="bulk">Bulk Date</ead:unitdate>) </ead:unittitle>
    <ead:physdesc label="Size: ">
        <ead:extent >Extent Statement</ead:extent>
            </ead:physdesc>
    <ead:origination label="Creator: ">
        <ead:persname >Creator's Name
                 </ead:persname>
            </ead:origination>
    <ead:langmaterial label="Language(s) of material: ">
        <ead:language langcode="eng">English</ead:language>. Other languages include <ead:language langcode="fre"
                    >French</ead:language>. </ead:langmaterial>
    <ead:abstract label="Abstract: ">Abstract here.</ead:abstract>
    <ead:physloc label="Storage note:">Storage note here.</ead:physloc>
        </ead:did>

Thanks for your help!

samjudson · February 5th, 2010, 05:41 AM

I don't usually do this, but here is the complete stylesheet. Hopefully you can see the purpose of the 4 different templates included.

Code:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ead="http://test.com"
                version="2.0">
    
   <xsl:strip-space elements="*"/>
   <xsl:output indent="yes" method="xml"/>

   <!-- Main template -->
<xsl:template match="ead">
      <ead:did>
         <xsl:apply-templates select="*"/>
      </ead:did>
   </xsl:template>

   <!-- Template for elements to ignore, but process inner children -->
<xsl:template match="archdesc | did">
      <xsl:apply-templates select="node()"/>
   </xsl:template>
        
      <!-- Template for elements to process -->   
      <xsl:template match="element()">
            <xsl:element name="ead:{local-name()}" namespace="http://test.com">
                     <xsl:copy-of select="@*"/>
                  <xsl:apply-templates select="node()"/>
            </xsl:element>
      </xsl:template>
      
      <!-- Template for elements to be ignored completely -->
      <xsl:template match="eadheader | repository"/>

</xsl:stylesheet>

learningxsl · February 5th, 2010, 09:26 AM

Thanks, Sam, this helps a lot. Appreciate it!