Hi,

I have some content as below:

<p style="FONT-FAMILY: Arial Black">sample text</p>

There can be many paragraph tags with different fonts. Now, I want to use XSLT to apply a unique font across all paragraphs.

I used below two codes but it doesn't do what i have expected.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xslutput method="html" omit-xml-declaration="yes"/>
<xsl:template match="p">
<p style="FONT-FAMILY: Arial">
<xsl:value-of select="." disable-output-escaping="yes"/>
</p>
</xsl:template>
</xsl:stylesheet>

--------------------------



<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xslutput method="html" omit-xml-declaration="yes"/>
<xsl:template match="/">

<xsl:for-each select="p">
<p style="FONT-FAMILY: Arial">
<xsl:value-of select="."/>
</p>
</xsl:for-each>

</xsl:template>
</xsl:stylesheet>

Can any one please fix any bug here?

Thanks in advance

Not really because you have failed to say a) What you want the output to look like, and b) why the code above isn't working, i.e. what is it outputting and what is wrong with it.

__________________
/- Sam Judson : Wrox Technical Editor -/

Think before you post: What have you tried?

please check the below examples:

Input: <p style="FONT-FAMILY: Arial Black">sample text</p>
Output: <p style="FONT-FAMILY: Arial">sample text</p>

Input: <p style="FONT-SIZE: 10pt; COLOR: #0000ff; FONT-FAMILY: Arial Black" xmlns="http://www.w3.org/1999/xhtml">sample text</p>
Output: <p style="FONT-SIZE: 10pt; COLOR: #0000ff; FONT-FAMILY: Arial" xmlns="http://www.w3.org/1999/xhtml">sample text</p>

I want to convert those inputs to the correspondign outputs. THe only change I want to do is FONT-FAMILY and apply Arial. But I'm unable to do that through XSLT though I have tried many variations :(

Please let me know, if you do require any other information.

Thanks again

basically whatever the code i have written is not getting applied and not effective to my input. The output is coming as just like inpue without changing Font-family.

Looks like a basic namespace problem: some of your examples show <p> elements in a namespace, others give no indication of whether the element is in a namespace or not. If you want to match p elements in the XHTML namespace, you need

<xsl:template match="h:p" xmlns:h="http://www.w3.org/1999/xhtml">

More typically, you will promote the namespace declaration to the xsl:stylesheet element.

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

I believe you asked me try this code:

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" method="html" indent="yes" cdata-section-elements="script"/>
<xsl:template match="h:p" xmlns:h="http://www.w3.org/1999/xhtml">
<p style="FONT-FAMILY: Arial">
<xsl:value-of select="."/>
</p>
</xsl:template>
</xsl:stylesheet>


When I tried this with the input


<p xmlns="http://www.w3.org/1999/xhtml">Sample Text</p>
<p style="FONT-SIZE: 9pt; FONT-FAMILY: Arial Black" xmlns="http://www.w3.org/1999/xhtml">Sample Text</p>
<p style="FONT-SIZE: 10pt; FONT-FAMILY: Garamond" xmlns="http://www.w3.org/1999/xhtml">Sample Text</p>


I have got below output:

<p>Sample Text</p><p style="FONT-SIZE: 9pt; FONT-FAMILY: Arial Black">Sample Text</p><p style="FONT-SIZE: 10pt; FONT-FAMILY: Garamond">Sample Text</p>

It seems to have removed namespace in the output

Can you please look into this where i'm doing mistake? This has really troubled me the whole day :(

Many Thanks

If you want your output elements to use the same name and namespace as the input, use <xsl:copy> rather than <p>. Alternatively, if you want to output a <p> element in the XHTML namespace, use <p xmlns="http://www.w3.org/1999/xhtml">. The system can't guess that you want your new <p> elements in a namespace - you have to tell it!

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

This below code fixed my issue

<xsl:stylesheet version="1.0" exclude-result-prefixes="xhtml" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xhtml="http://www.w3.org/1999/xhtml">
<xsl:output omit-xml-declaration="yes" method="xml" indent="yes" cdata-section-elements="script"/>
<xsl:template match="/">
<div xmlns="" class="content">
<xsl:apply-templates/>
</div>
</xsl:template>
<!-- match all nodes with an attribute style -->
<xsl:template match="@style">
<xsl:element name="{name()}">
<xsl:attribute name="style">font-family:Arial</xsl:attribute>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<!-- match all nodes with an attribute font-->
<xsl:template match="@font">
<xsl:element name="{name()}">
<xsl:attribute name="style">font-family:Arial</xsl:attribute>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<!-- match all tables -->
<xsl:template match="table">
<table xmlns="" cellspacing="0" cellpadding="0" border="1">
<xsl:attribute name="style">width:100%;</xsl:attribute>
<xsl:apply-templates/>
</table>
</xsl:template>
<!-- match all that's left -->
<xsl:template match="*|@*|text()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

That works does it? I find that hard to believe but I'm glad for you if it does.

Note, match="@font" shouldn't match elements WITH the font attribute, it should actually match the font attribute its self. match="*[@font]" would match elements with the font attribute.

__________________
/- Sam Judson : Wrox Technical Editor -/

Think before you post: What have you tried?

it didn't work ; i actually misread after posting here :( my output is below:
i tried your <xsl:template match="*[@font]"> but still the output is same

it really is eating me up!!

<p xmlns="http://www.w3.org/1999/xhtml">sample</p>
<p xmlns="http://www.w3.org/1999/xhtml">
<style style="font-family:Arial" xmlns=""></style>sample</p>
<p xmlns="http://www.w3.org/1999/xhtml">sample</p>
<p xmlns="http://www.w3.org/1999/xhtml"> </p>