XSLT Custom filter function

samjudson · March 29th, 2010, 12:01 PM

It depends on what you are trying to accomplish.

If you are trying to apply the the template to all the person elements where age > 18 and to all the person elements where age < $age then you would use | to create a union of the two groups. In the scenarios where $age is greater than 18 this would however mean it applies the template to all person elements.

<xsl:apply-templates select="$root/person_list/person[age < $age] | $root/person_list/person[age > 18]"/>

If you want to only apply the template to people who are between 18 and $age, then the filters should both appear within the predicate.

<xsl:apply-templates select="$root/person_list/person[age < $age and age > 18]"/>

Nasko26 · March 29th, 2010, 12:06 PM

Code:

<xsl:function name="my:name"> 
    <xsl:param name="name"/>
    <xsl:apply-templates select="contains($person[@name], $name])"/>
</xsl:function>

Thanks for the n-th time! I am really speechless now!
Just have another one: how do I filter by name then?

samjudson · March 29th, 2010, 12:38 PM

a) $person doesn't exist, unless you created it somewhere else and your just not telling us.
b) some of these questions appear to be fairly basic XSLT/XPath 101 type questions. Try having a look at a tutorial site like W3Schools: http://www.w3schools.com/xpath/xpath_syntax.as. You'll get more from learning the general rules, rather than asking us for specific examples.

If you still can't work it out then come back and let us know how you've progressed.

Nasko26 · March 29th, 2010, 12:58 PM

Yes, I forgot to mention. What I added myself is this declaration:

Code:

<xsl:variable name="person" select="/person_list/person"/>

Thanks for the page listed for reference, actually I am already familiar with all the information at w3schools on the subject (XML, XSL, XPath), and what I find hard to figure out is what I ask here.

I know that this example is suitable for the particular case:

Code:

title[@lang='eng']

but what I want is to check whether $person[@name] contains the parameter $name. Unfortunately, I get an error saying that I am giving an xs:boolean where a node() is expected.

Nasko26 · March 29th, 2010, 01:50 PM

Would you, please, help me here? I promise I won't be dwelling on the same subject anymore. I just need a proper solution for this, as I can't figure it out myself.

Thanks!

mhkay · March 29th, 2010, 01:54 PM

If you've got a new question, start a new thread. Don't keep asking supplementaries on the same thread. People lose track of what you've asked and what's been answered, and no-one wants to read through the whole thread to find out the context for the final question.

Nasko26 · March 29th, 2010, 04:31 PM

Code:

<xsl:apply-templates select="$person[contains(@name, $name)]"/>

Alright, here is my working solution finally. Thank you very much for the generosity! No sarcasm here - only to myself because it took me so long to figure it out on my own!

I'd really like to skip Mr Michael Kay's post above mine, I wish him good luck and all the best!