problem with xslt transformation

Enthrall · July 27th, 2010, 11:37 AM

Hi,
I am new to XSLT transformations.. and was trying the following code...

Code:

  <xsl:output method="html"/>
<xsl:template match="test">
    <html>
      <head>
        <style type="text/css">
      s1 { font-family: Arial; font-size: 12px }
    </style>
      </head>

      <p style="s1">
This is 
       <xsl:value-of select="test-Name"/>
from 
<xsl:value-of select="test-city"/>
      </p>
    </html>
  </xsl:template>
</xsl:transform>

I am expecting the output to be...

This is XYZ (Value in Name) from TEXAS ( value in city)..
however i am getting ...

This is from.

Let me know how to fix the issue?

samjudson · July 27th, 2010, 11:42 AM

You haven't shown us what your input XML looks like, so we really couldn't say.

Enthrall · July 27th, 2010, 11:46 AM

The input xml looks like this..

<asx:values>Â¶
<test>Â¶
<Name>Testn</Name>Â¶
<City>Texas</City>Â¶
</test>Â¶
</asx:values>Â¶

samjudson · July 27th, 2010, 11:51 AM

So you don't want "test-Name" you just want "Name".

Enthrall · July 27th, 2010, 11:53 AM

Quote:

Originally Posted by samjudson

So you don't want "test-Name" you just want "Name".

I want the output to be..
This is "Test" from 'Texas"

currently my output is This is from

samjudson · July 27th, 2010, 12:03 PM

There is no element in your XML called "test-Name". You have one called "test" and one called "Name".

You can refer to child elements in XPath by using the "/" character, e.g. select all "Name" elements who are children of a "test" element would be "test/Name".

However in your XSLT you are already inside the "test" element template, so you simply need to do <xsl:value-of select="Name"/> to get the value of the "Name" element.

mhkay · July 27th, 2010, 12:03 PM

Which part of Sam's answer didn't you understand? Your element is called "Name", it is not called "test-Name", so you need to change

Code:

<xsl:value-of select="test-Name"/>

to

Code:

<xsl:value-of select="Name"/>

Enthrall · July 27th, 2010, 12:47 PM

Quote:

Originally Posted by mhkay

Which part of Sam's answer didn't you understand? Your element is called "Name", it is not called "test-Name", so you need to change

Code:

<xsl:value-of select="test-Name"/>

to

Code:

<xsl:value-of select="Name"/>

thanks there...this solved the problem.

Enthrall · July 27th, 2010, 02:03 PM

How do I specify fonts for output?

samjudson · July 28th, 2010, 03:14 AM

That is no an XSLT question - you want a basic tutorial on CSS.

But based on your incorrect example above you want to define the CSS style as ".s1" not "s1" and then apply it to the paragraph element as <p class="s1">