Check the conditional expression inside the templace

metinhoclam · August 12th, 2010, 06:14 PM

I have the XML source document:

Code:

<?xml version="1.0" encoding="UTF-8"?>
<HELPDESK>
<board  group="PATHS" >
<board id="AC659FDE" group="PATH" source="C21D8443" target="09CF5CC8"/>
<board id="1C16BEC0" group="PATH" source="C21D8443" target="01DF2C05"/>
<board id="44D44B40" group="PATH" source="C21D8443" target="44A824A6"/>
<board id="1621GUJ00" group="PATH" source="C21D8443" target="44A824A7"/>
</board>

<board group="PRIVATE_ADDRESS">
<board id="C21D8443" group="CENTRE"/>
<board id="C21D8444" group="ADDRESS1"/>
<board id="01DF2C05" group="ADDRESS2" />
<board id="09CF5CC8" group="ADDRESS3" />
</board>

<board group="PUBLIC_PLACES" >
<board id="44A824A6" group="POSTOFFICE"/>
<board id="44A824A7" group="MARKET"/>
</board>
</HELPDESK>

----
My problem is to check if the target is not Public_places and print out the link with that information.
My template starts from board[group="CENTRE"]. How to print the information which shows the private address not the public places in the list?
Could you complete the conditional expression? [And] means only print the target place which not in public_places list

Code:

<xsl:template match="board[group='CENTRE']" mode="center">
<xsl:variable name="starting" select="."/> 
	<xsl:for-each select="$starting">		
		<letgo>
		 <xsl:attribute name="id"> <xsl:value-of select="@id"/> </xsl:attribute>
		 <xsl:attribute name="startat"> <xsl:value-of select="@group"/> </xsl:attribute>
		 <xsl:for-each select="../../board[group='PATH]">
		 <xsl:if test="$starting[@id = current()/@source] and"  >
			<guidedirection>
				<xsl:attribute name="id"> <xsl:value-of select="@id"/> </xsl:attribute>
				<xsl:element name="startingpoint"> <xsl:value-of select="@source"/> </xsl:element>
				<xsl:element name="destination"> <xsl:value-of select="@target"/> </xsl:element>					
			</guidedirection>
		 </xsl:if>
	         </xsl:for-each>
		</letgo>		
	</xsl:for-each>
</xsl:template>

mhkay · August 12th, 2010, 06:36 PM

>How to print the information which shows the private address not the public places in the list?

Sorry, I don't understand what that means in terms of your data.

Your code is rather convoluted and I would start by changing it to something like this:

Code:

<xsl:template match="board[group='CENTRE']" mode="center">
  <letgo id="{@id}" startat="{@group}">
  <xsl:for-each select="//board[@group='PATH and @source=current()/@id]">
    <guidedirection id="{@id}">
      <startingpoint> 
         <xsl:value-of select="@source"/>
      </startingpoint>
      <destination>
         <xsl:value-of select="@target"/>  
      </destination>
    </guidedirection>
  </xsl:for-each>
  </letgo>		
</xsl:template>

metinhoclam · August 12th, 2010, 06:47 PM

@mhkay's : It looks better with your modifying. But with that template, we can export all path. I means just export the information which have target not in public place.
<board id="AC659FDE" group="PATH" source="C21D8443" target="09CF5CC8"/>
<board id="1C16BEC0" group="PATH" source="C21D8443" target="01DF2C05"/>
not for all.

mhkay · August 12th, 2010, 06:58 PM

Add a global variable containing all the public places ids:

Code:

<xsl:variable name="public-ids" select="//board[@group='PUBLIC PLACES']/group/@id"/>

and then add to the xsl:for-each

Code:

<xsl:for-each select="//board[@group='PATH 
                              and @source=current()/@id 
                              and not(@target=$public-ids)]">

metinhoclam · August 13th, 2010, 05:52 AM

@mr.mhkay: it works...thanks you.