XML tags are not getting displyed in IE

nagarathnabillawa · September 20th, 2010, 03:33 AM

Hi,,

I am new to XSLT and I am trying to transform xml to another xml using XSLT.
When I tried to open output xml in IE ,xml tags are not getting displayed.Only text is getting displayed.
Can someone help me out in this?
Thanks in advance.

joefawcett · September 20th, 2010, 03:41 AM

Sounds like IE is treating the file as an HTML one. In that case unrecognised tags are ignore and their content is displayed.
Can you show a small example of the output and what the file is called?
On a side issue IE is not a suitable development environment for XML/XSLT. You'd be better off using a dedicated IDE such as oXygen, or Altova's XML Spy. Alternatively Kernow provides a GUI over the Saxon proccessor.

nagarathnabillawa · September 20th, 2010, 04:02 AM

Thanks joefawcett.
Here are my XML and XSL files.

XML file:
<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="new.xsl"?>
<catalog>
<cd>
<title>Empire Burlesque</title>
<artist>Bob Dylan</artist>
<country>USA</country>
<company>Columbia</company>
<price>10.90</price>
<year>1985</year>
</cd>
<cd>
<title>Hide your heart</title>
<artist>Bonnie Tyler</artist>
<country>UK</country>
<company>CBS Records</company>
<price>9.90</price>
<year>1988</year>
</cd>
</catalog>

XSL file:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:element name="root">
<xsl:for-each select="catalog/cd">
<xsl:element name="singer">
<xsl:value-of select="artist" />
</xsl:element>
<br />
</xsl:for-each>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

And I am getting " Bob Dylan
Bonnie Tyler"

as output in IE.

joefawcett · September 20th, 2010, 04:58 AM

Well I concur, IE just shows the data. I'm not sure why. I've seen similar things before though, for some reason IE treats the output as HTML even when it's not.

ptn77 · September 20th, 2010, 02:30 PM

Do you have to put the tags within the

Code:

 <xsl:text>

in order for the tags to show up in the browser?
So in the xsl you would have something like the following:

Code:

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:element name="root">
<xsl:text><![CDATA[<root> ]]></xsl:text>
<xsl:for-each select="catalog/cd">
<xsl:element name="singer">
<xsl:text><![CDATA[<singer>]]></xsl:text><xsl:value-of select="artist" /><xsl:text><![CDATA[</singer>]]></xsl:text>
</xsl:element>
<br />
</xsl:for-each>
<xsl:text><![CDATA[</root>]]></xsl:text>
</xsl:element>
</xsl:template>
</xsl:stylesheet>

I'm new to xslt too.

Thanks,

Martin Honnen · September 20th, 2010, 02:41 PM

If you want to use XSLT to transform XML to XML and that XML is not something the browser knows to render (e.g. like XHTML which IE 6, 7, 8 and Mozilla and Opera can render or like SVG which Opera and Mozilla can render or which IE 9 can render) then the browser is not the right tool to run and test that transformation. Use a standalone XSLT processor or an XML editor which allows you to see the source of the transformation result.

nagarathnabillawa · September 23rd, 2010, 06:15 AM

Thanks Martin.. Let me try with some xslt processor!!