Adding the namespaces using XSLT

sivakumar_g01 · October 20th, 2010, 11:37 AM

Hi All,

I had a requirement of adding the namespaces to the input XML using XSLT. I am novice to XSLT and with the knowledge from the XSLT2.0 book, i came up with following XSLT to achieve the same.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:param name="uri" />

<xsl:template match="comment()|processing-instruction()|/">
<xsl:copy>
<xsl:apply-templates />
</xsl:copy>
</xsl:template>
<xsl:template match="*">
<xsl:element name="fnz1:{local-name()}" namespace="{$uri}">
<xsl:apply-templates />
</xsl:element>
</xsl:template>
</xsl:stylesheet>

But because of this namespace is coming on each element.

input XML is shown below and uri variable is http://www.namspace.com
<RootElement>
<element1> </element1>
<element2> </element2>
</RootElement>

<RootElement xmlns:fnz1="http://www.namspace.com">
<element1 xmlns:fnz1="http://www.namspace.com"> </element1>
<element2 xmlns:fnz1="http://www.namspace.com"> </element2>
</RootElement>

Please let me know how can i resolve this issue and i had to use only XSLT1.0.

Thanks & Regards
Siva

Martin Honnen · October 20th, 2010, 11:51 AM

Which XSLT processor do you use? When I use Saxon 6.5.5 which is an XSLT 1.0 processor then I get

Code:

<?xml version="1.0" encoding="utf-8"?><fnz1:RootElement xmlns:fnz1="http://example.com">
<fnz1:element1> </fnz1:element1>
<fnz1:element2> </fnz1:element2>
</fnz1:RootElement>

as the output.

mhkay · October 20th, 2010, 12:02 PM

A conformant processor is perfectly entitled to include redundant namespace declarations in the output, but it's not a very smart thing to do. Find a better processor.

samjudson · October 20th, 2010, 12:04 PM

If you notice though, the namespace in his output has a prefix, which the elements don't - therefore they aren't actually in that namespace.

So his processor is definitely not producing the correct output.

sivakumar_g01 · October 29th, 2010, 07:22 AM

Hi,

First my apologies as i did not put the correct xslt i am using. Following is the XSLT that i am using.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:param name="nameSpaceURI" />
<xsl:template match="comment()|processing-instruction()|/">
<xsl:copy>
<xsl:apply-templates />
</xsl:copy>
</xsl:template>
<xsl:template match="input">
<xsl:element name="fnz:{local-name()}" namespace="http://www.namespace1.com">
<xsl:apply-templates />
</xsl:element>
</xsl:template>
<xsl:template match="*">
<xsl:element name="fnz1:{local-name()}" namespace="{$nameSpaceURI}">
<xsl:apply-templates />
</xsl:element>
</xsl:template>
</xsl:stylesheet>

And following is the input that i am sending and along with value for parameter namespaceURI. The input element will assume one namespace and other elements assumes another namespace.
<input>
<element1>
<element2>
</input>

With the above XSLT and input, the namespace is being redefined for each and every element within the input element like below.
<fnz:input xmlns:fnz:"http://www.namespace1.com">
<fnz1:element1 xmlns:fnz1:"http://www.namespace2.com">
<fnz1:element2 xmlns:fnz1:"http://www.namespace2.com">
</input>

Thanks & Regards
Siva

mhkay · October 29th, 2010, 07:37 AM

And (let me check) what you want is for the namespace xmlns:fnz1:"http://www.namespace2.com" to be declared on the outermost element fnz:input even though it is not actually used at that level?

In XSLT 2.0, putting an "unused" namespace on an element can easily be achieved using the xsl:namespace instruction. In XSLT 1.0 you need to be a bit more devious. The technique is to create a dummy element in this namespace and then copy the namespace node:

Code:

<xsl:variable name="dummy">
  <xsl:element name="fnz1:dummy" namespace="{$namespaceURI}"/>
</xsl:variable>
<fnz:input>
  <xsl:copy-of select="$dummy//namespace::fnz1"/>
  ...
</fnz:input>