Loading url

actionjezus6 · May 18th, 2011, 02:23 PM

Hi,
I am very new to programming, and I have this problem - I want to load url from xml, and use it as a link on page created via xsl. After some not so short time spent on finding way to do it I have finally manged to, but it occurs that this little bastard adds "/" at the end of my url, making it utterly useless :/

for example: url is <link>whatever1.xml</link>, and after xsl-magic my browser really want to open "whatever1.xml/", which obviously does not make me happy :/

Sorry for exotic names, and thanks in advance for help.

Here's my xml:

Code:

?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<?xml-stylesheet type="text/xsl" href="transformacja.xsl"?>
<katalog>
    <ryba>
    <nazwa>Ryba 1</nazwa>
    <latin>Pisces 1</latin>
    <link>ryby/ryba1.xml/</link>
</ryba>
</katalog>

And here is my xsl

Code:

<?xml version="1.0" standalone="no"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:template match="/">
    <html>
      <head>
        <title>Atlas Ryb - Indeks</title>
        <style type="text/css">
          body
          {
          margin:10px 10px 10px 10px;
          background-image:url('images/01.jpg');
          color: #5F8700;
          text-align: justify;
          font-family: Georgia, "Times New Roman", Times, serif;
          font-weight: normal;
          letter-spacing: -1px;
          font-size: 1.0em;
          }
        </style>
      </head>
      <body>
        <center>
          <img src="images/ObrazekIndeks.gif"/>
          <h2>XXXXXXXXXXXXXXXXXXX</h2>
          <p>YYYYYYYYYYYYYYYYY</p>
          
          <table style="width:80%;" border="0">
            <tr>
              <td width="33,33%" align="center">dfhg</td>
              <td width="33,33%" align="center">sdfg</td>
              <td width="33,33%" align="left">sdfg</td>
            </tr>
          </table>
          
          <xsl:apply-templates/>
        </center>
      </body>
    </html>
  </xsl:template>

  
  
  <xsl:template match="katalog">
    <xsl:for-each select="ryba">
      <xsl:sort select="nazwa"/>
      <table style="width:80%;" border="0">
        <tr>
          <td width="33,33%" align="center">
            <xsl:value-of select="nazwa"/>
          </td>
          <td width="33,33%" align="center">
            <xsl:value-of select="latin"/>
          </td>
          <td width="33,33%" align="left">
          <a>
        <xsl:attribute name="href">
          <xsl:value-of select="link"/>
        </xsl:attribute>Zobacz
      </a>
          </td>
        </tr>
      </table>
    </xsl:for-each>
    <a href="niewiemco.xml">
      <p>Zobacz wszystkie ryby</p>
    </a>
  </xsl:template>

</xsl:stylesheet>

mhkay · May 18th, 2011, 05:54 PM

Very often if a "/" appears magically at the end of a URL, it's because the web server itself issued a redirection request: that is, you asked for "abc.xml", and the web server replied saying please ask for "abc.xml/" instead; so "abc.xml/" is what appears in the browser address bar. If the redirected address doesn't work, then the server seems to be misconfigured. This is nothing to do with XSLT.

actionjezus6 · May 18th, 2011, 06:06 PM

Many Thanks.
I've noticed that only 4 links were malformed.
Somehow, when I've re-written xml content, everything is working just fine...

Anyhow, this thread can be closed, deleted or whatever :)