Place a variable in html hyperlink for option in xsl:choose

Barry_T · December 14th, 2011, 07:11 PM

Hi,
First time poster, and very new to XML and XSL. My question is this, I have a table which is sorted using xsl sort. I would like to sort it ascending when the parameter equals a certain value, say 'sortTime', otherwise sort it descending. I was hoping to set this parameter to that value using a hyperlink. I have searched high and low, and still dont even know about setting up a parameter correctly so I dont know if that is the issue or if this can even be done. Here is my code:
Any help or direction to information will be greatly appreciated.
Kind Regards
Barry T

Code:

<?xml version="1.0" encoding="ISO-8859-1"?>
<!-- Edited by XMLSpyÂ® -->
	<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	  	<xsl:template match="/">
	  	<xsl:param name="sortkey" />
<html>
	<head>
		<meta content="text/html; charset=utf-8" http-equiv="Content-Type" />
		<title>Euro 2012 Assignment</title>
		<script language="javascript" type="text/javascript" src="weatherRss.js"></script>
		<script language="javascript" type="text/javascript" src="showRSS1.js"></script>
		
		
		
		<link rel="stylesheet" type="text/css" href="stylesheet1.css" />
		<!--link rel="stylesheet" type="text/css" href="football.css" /-->
	</head>

<body style="font-family:Arial;font-size:12pt;background-color:#EEEEEE">
<h2><strong>RSS news feeds</strong></h2>
<br/>
<div class="centerback">
		
	<div class="fixturesTable">
	   	
	   	<form method="GET" action="" name="form1">
			<table border="4" style="color:white; white-space: nowrap;" id="tableFix">
		   
		        <tr style="color:white;" bgcolor="silver">
			        <td>Team Name</td>
			        <td>.</td>
			        <td>Team Name</td>
			        <td>Venue</td>
			        <td><a href="football.xml?sortkey=sortTime">Time</a></td>
		        </tr>
		        
		        
		  		
		  		<xsl:choose>
		    		<xsl:when test="sortkey=sortTime">
		       			<xsl:for-each select="fixture/game">
		  					<xsl:sort select="time" order="ascending"></xsl:sort>
		   				        <tr style="color:silver;">
							        <td><xsl:value-of select="teamA"/></td>
							        <td> VS </td>
							        <td><xsl:value-of select="teamB"/></td>
						        	<td><xsl:value-of select="venue"/></td>
							        <th value="qwe" id="timeRow"><xsl:value-of select="time"/></th>
						        </tr>
						</xsl:for-each>
		    		</xsl:when>
		    	
		    		<xsl:otherwise>
		    			<xsl:for-each select="fixture/game">
		  					<xsl:sort select="time" order="descending"></xsl:sort>
		   				        <tr style="color:silver;">
							        <td><xsl:value-of select="teamA"/></td>
							        <td> VS </td>
							        <td><xsl:value-of select="teamB"/></td>
						        	<td><xsl:value-of select="venue"/></td>
							        <th value="qwe" id="timeRow"><xsl:value-of select="time"/></th>
						        </tr>
						</xsl:for-each>
		    		</xsl:otherwise>
		   		</xsl:choose>
		   	</table>
		    <input type="submit" name="btn" value="alert" onclick="" />
	    </form>
	    
	</div>

</div>

<div class="rightside"></div>
<div class="leftside"></div>
  	
   	    
 	</body>
  	</html>
	</xsl:template>
</xsl:stylesheet>

mhkay · December 14th, 2011, 07:59 PM

First point is that to answer questions about XSLT, we really need to know whether you are using XSLT 1.0 or XSLT 2.0. Using 2.0 makes a lot of things easier, but it isn't available in all environments.

The general structure of the solution is likely to be something like this:

Code:

<xsl:variable name="order" select="if (...) then 'ascending' else 'descending'"/>
<xsl:for-each ...>
   <xsl:sort select="..." order="{$order}"/>
   ...
</xsl:for-each>

except that the if-then-else is XSLT 2.0, and in 1.0 you'll need to use the more long-winded xsl:choose.

Barry_T · December 14th, 2011, 09:16 PM

Thank you for a very prompt reply! I am using XSLT 1.0
I will give it a go, Thanks for your help.
Kind Regards
Barry_T