Need help adding if condition

kakhtar · December 21st, 2011, 10:56 PM

Hello:
I know very little XSL, but need to modify some code to add an if condition. Code (given below) generates filename (e.g. "28867_John_1100002275_D009_List of contents_20111221.pdf"). I need to be able to change part of filename from "List of contents" to "Table of contents". I think code like below should do it but not sure where to add it in code:

Code:

                <xsl:if $DocumentName="List of contents">
                                <xsl:value-of select="Table of contents"/>
                </xsl:if>

Quick help on this will save me a lot of batch processing. Thanks in advance.

Here is the code I need to modify:

Code:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:e="http://www.taleo.com/ws/ob800/2009/04" xmlns:fct="http://www.taleo.com/xsl_functions" exclude-result-prefixes="e fct">
	<xsl:output method="xml" encoding="UTF-8" omit-xml-declaration="yes"/>
	<xsl:param name="OUTBOUND_FOLDER"/>
	<xsl:template match="/">
	
		<files>
			<xsl:apply-templates select="//e:OnboardingProcessDocument"/>
 <!-- here -->
		</files>
	</xsl:template>
	<xsl:template match="e:OnboardingProcessDocument">
 <!-- here --> 
		<xsl:variable name="EmployeeID" select="../../e:Assignment/e:Assignment/e:TalentMasterFile/e:TalentMasterFile/e:User/e:User/e:EmployeeID"/>
		<xsl:variable name="DocumentCode" select="e:Document/e:FileBasedDocument/e:Code"/>
		<xsl:variable name="DocumentName" select="normalize-space(e:Document/e:FileBasedDocument/e:Name)"/>
		<xsl:variable name="DateCreated" select="../../e:RuntimeFields/e:RuntimeField[@name='Now']"/>
		<xsl:variable name="LastName" select="../../e:Assignment/e:Assignment/e:TalentMasterFile/e:TalentMasterFile/e:User/e:User/e:LastName"/>
		<xsl:variable name="RequisitionNumber" select="../../e:Assignment/e:Assignment/e:Position/e:Position/e:RequisitionNumber"/>
		<xsl:variable name="filename" select="fct:normalize-filename(concat($EmployeeID, '_', $LastName, '_', $RequisitionNumber, '_', $DocumentCode, '_', $DocumentName, '_', $DateCreated, '.pdf'))"/>
		<file path="{concat($OUTBOUND_FOLDER, '/', $filename)}">
			<content>
				<xsl:value-of select="e:content"/>
			</content>
			<Filename>
				<xsl:value-of select="$filename"/>
			</Filename>
			<EmployeeID>
				<xsl:value-of select="$EmployeeID"/>
			</EmployeeID>
			<DocumentCode>
				<xsl:value-of select="$DocumentCode"/>
			</DocumentCode>
			<DocumentName>
				<xsl:value-of select="$DocumentName"/>
			</DocumentName>
			<RequisitionNumber>
				<xsl:value-of select="$RequisitionNumber"/>
			</RequisitionNumber>
			<LastName>
				<xsl:value-of select="$LastName"/>
			</LastName>
			<DateCreated>
				<xsl:value-of select="$DateCreated"/>
			</DateCreated>
		</file>
	</xsl:template>
	<!-- ======================================= -->
	<!-- Normalize filename, replacing invalid characters with '_'. -->
	<!-- ======================================= -->
	<xsl:function name="fct:normalize-filename">
		<xsl:param name="filename"/>
		<xsl:value-of select="replace(replace(translate($filename, '\\\/:*?|', '_'), '&lt;', '_'), '&gt;', '_')"/>
	</xsl:function>
</xsl:stylesheet>

mhkay · December 22nd, 2011, 02:38 PM

Firstly, your syntax isn't quite right. The nearest would be something like

Code:

<xsl:if test="$DocumentName='List of contents'">
     <xsl:value-of select="'Table of contents'"/>
</xsl:if>

though the following is shorter:

Code:

<xsl:if test="$DocumentName='List of contents'">Table of contents</xsl:if>

But then there's the question of where you intend to put this code. You're calculating the filename inside a function where the variable $DocumentName isn't available. So you may need to add it as an extra paramter.

kakhtar · December 22nd, 2011, 02:52 PM

Thanks Michael.
Unfortunately I am novice trying to make this code work. Would you be kind enough to modify as needed to achieve desired results?

mhkay · December 22nd, 2011, 03:25 PM

No, sorry, I'm prepared to answer questions about XSLT but I'm not prepared to write your code for you. You should not attempt to modify a working stylesheet until you have a basic knowledge of the language.

kakhtar · December 22nd, 2011, 03:32 PM

Fair enough. Thanks for looking into it anyway.

mrame · December 23rd, 2011, 07:47 AM

I could not understand ur need. Please post a minimal XML and the expected output from that. Show some examples on your requirement.