Hi everybody,

I'm new to XSL and I need some help. My goal is to generate multiple .xml files which differs only by the content of one tag. Here an example:

The original .xml file has the form:

<root>
<a>
[...]
</a>
<b>
[...]
</b>
<c>
[...]
</c>
<d>
<t1>
</t1>
<t2>
</t2>
<t3>
</t3>
</d>
</root>

and I would like to generate 3 different files:

<root>
<a>
[...]
</a>
<b>
[...]
</b>
<c>
[...]
</c>
<d>
<NEW>
</NEW>
<t2>
</t2>
<t3>
</t3>
</d>
</root>

<root>
<a>
[...]
</a>
<b>
[...]
</b>
<c>
[...]
</c>
<d>
<t1>
</t1>
<NEW>
</NEW>
<t3>
</t3>
</d>
</root>

<root>
<a>
[...]
</a>
<b>
[...]
</b>
<c>
[...]
</c>
<d>
<t1>
</t1>
<t2>
</t2>
<NEW>
</NEW>
</d>
</root>


have you got any ideas (I'm using xsl 2.0)?

Best,
Axon

Something like this, perhaps:

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

thanks a lot Michael for your answer!

For the specific example it will probably work. Sadly I'm dealing with more complex xml sources, i.e. t1, t2, t3 are indeed all equal (<t1>=<t2>=<t3>=<t>) and I don't know in advance how many occurrences of <t> are there.

For this reason I cannot do different matches like:

<xsl:template match="t1" mode="m1">
<NEW/>
</xsl:template>

Here the new correct input file:
<root>
<a>[...]</a>
<b>[...]</b>
<c>[...]</c>
<d>

[...]

<t></t>
<t></t>
<t></t>

[...]

</d>
</root>

and the expected result files:
1)
<root>
<a>[...]</a>
<b>[...]</b>
<c>[...]</c>
<d>

[...]

<new/>
<t></t>
<t></t>

[...]

</d>
</root>

2)
<root>
<a>[...]</a>
<b>[...]</b>
<c>[...]</c>
<d>

[...]

<t></t>
<new/>
<t></t>

[...]

</d>
</root>

3)
<root>
<a>[...]</a>
<b>[...]</b>
<c>[...]</c>
<d>

[...]

<t></t>
<t></t>
<new/>

[...]

</d>
</root>


I'm so sorry if I made you waste time with a non-general example.
Thanks again for your reply.

Best,
Axon

Try changing

to

etc.

__________________
/- Sam Judson : Wrox Technical Editor -/

Think before you post: What have you tried?

Thanks for your suggestions. I was able to solve the issue in a slightly different way, but your hints has been super useful!!!

Here the solution I designed (the XPaths are a bit more complex w.r.t the example and I also needed to perform a check on an attribute ^_^):

<xsl:template match="/">

<xsl:for-each select="a/b/c/d/e/f[attribute::name = 'blablabla']">

<xsl:variable name="currNode" select="position()"/>
<xsl:variable name="uri" select="concat('multi_',$currNode,.xml')"/>
<xsl:result-document href="{$uri}">

<xsl:apply-templates select="../../../../../../*">
<xsl:with-param name="counter" select="$currNode"/>
</xsl:apply-templates>

</xsl:result-document>

</xsl:for-each>

</xsl:template>

<xsl:template match="node( ) | @*">

<xsl:param name="counter"/>
<xsl:copy>
<xsl:apply-templates select="@* | node( )">
<xsl:with-param name="counter" select="$counter"/>
</xsl:apply-templates>
</xsl:copy>

</xsl:template>

<xsl:template match="d/e/f">

<xsl:param name="counter"/>
<xsl:choose>

<xsl:when test="self::node()[attribute::name = 'blablabla'] and position()=$counter*2"><NEW name="NEW"/></xsl:when>
<xsl:otherwise>

<xsl:copy>
<xsl:apply-templates select="@* | node( )">
<xsl:with-param name="counter" select="$counter"/>
</xsl:apply-templates>
</xsl:copy>

</xsl:otherwise>

</xsl:choose>

</xsl:template>


The use of <xsl:apply-templates select="../../../../../../*"> was necessary in order to get the whole original file copied, otherwise, only the changed part of the tree were displayed in the result files. I know that probably there are better solutions (with a cleaner and simplier style) but this seems to work and for now I'll keep it :D

Another question: Do you know why I had to use "position()=$counter*2"? By using only position()=$counter when $counter was equal 1 no changes occurred, and when it was equal 2 only the first occurrence of <f name='blablabla'> where changed.

Thanks again for your help!!!
Axon

The "../../../../../../*" could probably just be changed to "/*".

__________________
/- Sam Judson : Wrox Technical Editor -/

Think before you post: What have you tried?