Deletion of element from XML by specifying a condition

saralay · March 11th, 2013, 07:46 AM

Thank you Martin,

I dont have version 2.0 when i want to get the same output with version 1.0 what logic I should use.

Thanks in advance

Sarala

Martin Honnen · March 11th, 2013, 08:31 AM

Use what has been suggested, namely the identity transformation template

Code:

<xsl:template match="@* | node()">
  <xsl:copy>
    <xsl:apply-templates select="@* | node()"/>
  </xsl:copy>
</xsl:template>

plus a template that ensure the elements you want to remove are not copied, namely

Code:

<xsl:template match="ItemMaster/Item[ItemId = /Transmission/Items/ItemId]"/>

so putting these together results in

Code:

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="1.0">
  
<xsl:strip-space elements="*"/>
<xsl:output indent="yes"/>

<xsl:template match="@* | node()">
  <xsl:copy>
    <xsl:apply-templates select="@* | node()"/>
  </xsl:copy>
</xsl:template>

<xsl:template match="ItemMaster/Item[ItemId = /Transmission/Items/ItemId]"/>

</xsl:stylesheet>

saralay · March 11th, 2013, 08:37 AM

Thanks a lot Martin

Sarala