Hi people!, im trying to generate jsf pages from an xml using an xslt stylesheet, i have a problem now, that i cant generate an output like this:

<h:panelGroup rendered="#{beanXML.especialidad.nombre=='Cardiope diatria'}">

the output that im getting is:


<h:panelGroup rendered="#beanXML.especialidad.nombre=='Cardioped iatria'">

the {} are missing,

im using this xsl style sheet:

<xsl:template match="especialidad">
<h:form>
<h:panelGroup rendered="#{../@valor}=='{@nombre}'">
..

The xml file is:

<setcon valor="beanXML.especialidad.nombre">

<especialidad nombre="Cardiopediatria" tipoconsulta="#{beanXML.tipoConsulta}">



i must compare the property of a bean (beanXML.especialidad.nombre) in java with a value of a property ( nombre) in the xml, ive tryeid using xsl:text
and puting the values of {='{' and }='}' like i did with #= '#' but its nots working net beans say unable to parse
im using com.sun.org.apache.xalan.internal.xsltc.trax.Trans formerImpl - default JRE XSLT processor.

this is the header of my xsl style sheet:

xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
xmlns="http://www.w3.org/1999/xhtml"
xmlns:ui="http://java.sun.com/jsf/facelets"
xmlns:f="http://java.sun.com/jsf/core"
xmlns:h="http://java.sun.com/jsf/html">
<xsl:output method="html"/>


hope u can help! please!

You can use doubled curly braces in an AVT to output a literal curly brace. So it would be

__________________
Michael Kay
http://www.saxonica.com/
Author, XSLT 2.0 and XPath 2.0 Programmer\'s Reference

Thanks a lot! :), worked fine, now i can cont with my job! ty again!

Hello! I'm also using XSLT to render a XHTML page in JSF. Do you use a Java Transformer to make the XSLT or how does your setup looks like?